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GenaCL600 [577]
3 years ago
6

What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes th

rough a diffraction grating that has 500.0 lines per mm?
236 nm
353 nm
943 nm
1414 nm
Physics
2 answers:
max2010maxim [7]3 years ago
7 0

Answer:

its D

Explanation:

edg2020

Bond [772]3 years ago
6 0

Answer:

D) 1414 nm

Explanation:

This is correct on Edge.

Using the equation dsin(angle)=n(wavelength), we can solve for wavelength.

First we must convert the 500 lines per mm to nm. We do this by 1/500, giving you 0.002. Then move the decimal over six places to the right, resulting in 2000.

Then by plugging in the other values, we have 2000sin(45)=1(wavelength).

N is one because we are just solving for a first-order band.

So 2000sin(45)=wavelength

By using a calculator, we can see that the wavelength equals approximately 1414nm.

I hope this helped. If it did, I would really appreciate a Brainliest!!

Have a great day:)

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