Answer:

Explanation:
The question is missing an image. I have added this as an attachment to my answer.
Given;
Q = total charge
R = radius of cylindrical shell
h = height of cylindrical shell
d = distance of point from the right side of the cylinder
Let the thickness of the cylindrical shell be
, and the charge
,
Now, using the formula for finding the electric field due to a ring at a chosen point:

where
= center of the ring to the point
= electrostatic constant
We integrate on both sides from the limits
to
in order to determine the electric field at the point 
= 
To consider the molecule in gas at rest, suppose a container of gas at rest.
We know that velocity is a vector quantity and it includes direction but speed is a scalar quantity and it does not include a direction.
Although the molecules are moving around a lot, they are only moving around within the fixed walls of the container. As the container isn't moving (given), the net velocity of the gas molecules is zero. Think about their random movements as vectors, then think about adding up all those vectors over time. They cancel each other out over time. So, the average velocity of a molecule in gas at rest is zero.
But it's only the directions that cancel each other out, which is why the average speed (ignoring direction) is non-zero.
To learn more about average speed refer to the link:
brainly.com/question/12322912
#SPJ4
<span>It is possible to determine which cart to which ch is connected if the graph would show electrical charge, ie, amps or voltage. If the graph showed a series circuit diagram this would also allow determination. Bottom line is that a correct graph data will show the requested information.</span>
Mg = 6.2 x 9.81 = 60.822
This is also normal force.
Coefficient of friction times normal force is the force due to friction:
60.822 x 0.24 = 14.6N
F = MA so F(your force) - F(friction) = 6.2 x 0.5
= 3.1
Your answer is 3.1+ 14.6
I hope this is correct though I might be wrong.
Answer:
I would say false
Explanation:
Because friction slows it down which means when the object bounces back it will not have the same energy or force that was applied before.