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kow [346]
3 years ago
9

What is providing the centripetal force in the following examples?

Physics
2 answers:
umka2103 [35]3 years ago
8 0
A yo-yo swung in a circle.
worty [1.4K]3 years ago
3 0
The yo yo being swung around in a circle is an example of centripetal
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According to the FITT Principle you should exercise how many days ?
hjlf
You should exercise 2-3 times per week
4 0
2 years ago
Ondrea could drive a Jetson's flying car at a constant speed of 540.0 km/hr across oceans and space, approximately how long woul
Tcecarenko [31]

Answer:

The time taken in years is   x = 125 \  years

Explanation:

From the question we are told that

   The  speed is  v  = 540.00 \ km /hr  =  \frac{540 *1000}{3600} =  150\  m/s

    The distance from the sun to Pluto is  d =  5.9*10^{9} \  k m =  5.9*10^9 * 1000 =  5.9*10^{12} \  m

Generally the time  taken is mathematically represented as

     t =  \frac{d}{v}

=>   t = \frac{5.9*10^{11}}{150}

=>   t =  3.933*10^{9}

Converting to years

   1 year  \to  3.154*10^7 \  s

    x \  years  \to 3.933*10^{9}

=>  x = \frac{ 3.933*10^{9} * 1 }{ 3.154 *10^7}

=>    x = 125 \  years

7 0
3 years ago
What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 N at an angle of 35° above the
Olegator [25]

The acceleration of the wagon along the ground is 3.6 m/s².

To solve the problem above, we need to use the formula of acceleration as related to force and mass.

Acceleration: This can be defined as the rate of change of velocity.

⇒ Formula:

  • Fcos∅ = ma................. Equation 1

⇒ Where:

  • F = Force
  • ∅ = angle above the horizontal
  • m = mass of the wagon
  • a = acceleration of the wagon

⇒ make a the subject of equation 1

  • a = Fcos∅/m..................... Equation 2

From the question,

⇒ Given:

  • F = 44 N
  • ∅ = 35°
  • m = 10 kg

⇒ Substitute these values into equation 2

  • a = 44(cos35°)/10
  • a = 44(0.8191)/10
  • a = 3.6 m/s²

Hence, The acceleration of the wagon along the ground is 3.6 m/s²

Learn more about acceleration here: brainly.com/question/9408577

3 0
2 years ago
A regulation basketball has a 15 cm diameter and may be appropriated as a thin spherical shell.
REY [17]

Solution :

From the given data,

For the spherical shell is $\frac{k^2}{R^2}= \frac{2}{3}$

where x is the radius of gyration and the acceleration of a rolling body on an inclined plane = a

Therefore,

$a =\frac{g \sin \theta}{1+ \frac{k^2}{R^2}} $

  $= \frac{g \sin \theta}{1 +\frac{2}{3}}$

  $= \frac{3}{5} g \sin \theta$

  = 0.6 x 9.81 x sin ( 29.7)

  $= 2.913 \ m/s^2$

$h = \frac{1}{2} a(\Delta t)^2$

$\Delta t = \sqrt{\frac{2h}{a}}$

$\Delta t = \sqrt{\frac{2 \times 2.9}{2.913}}$

Δt = 1.411 s

6 0
2 years ago
PLEASE HELP! Two 3.5 g bullets are fired with speeds of 44.6 m/s and 62.6 m/s, respectively.
Ivahew [28]

Answer:

c) What is the ratio K2/K1 of their kinetic energies?

Explanation:

8 0
3 years ago
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