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2 years ago

Two objects of different mass rest on Earth. Which one experiences the greater acceleration due to gravity ?

1 answer:

3 0

the answer is a because if two objects of diffrent mass are on tge earth, the object that would recive greather acceleration on gravity, wouldbe none.

it would be none cuz since two objects are on the earth, it ha sthe same gravitational piull, from the other object.

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Consider a uniformly charged thin-walled right circularcylindrical shell having total charge Q, radiusR, and height h. Determine

Vinil7 [7]

Answer:

$\frac{k_eQ}{2h}$

Explanation:

The question is missing an image. I have added this as an attachment to my answer.

Given;

Q = total charge

R = radius of cylindrical shell

h = height of cylindrical shell

d = distance of point from the right side of the cylinder

Let the thickness of the cylindrical shell be $dx$ , and the charge $\frac{Qdx}{h}$ ,

Now, using the formula for finding the electric field due to a ring at a chosen point:

$dE = \frac{k_ex}{(x^2 + R^2)^{\frac{3}{2}}} {\frac{Qdx}{h}i}$

where $x$ = center of the ring to the point

$k_e$ = electrostatic constant

We integrate on both sides from the limits $d$ to $d + h$ in order to determine the electric field at the point $E$

$\int\limits dE$ = $\int\limits^{d + h}_d {\frac{k_eQxdx}{h(x^2 + R^2)^{\frac{3}{2}}}i}$

$E = \int\limits^{d + h}_d {\frac{k_eQdx}{h(x^2 + R^2)^{\frac{3}{2}}}i} = \frac{k_eQ}{2h}$

6 0

3 years ago

The intensity of light from a central source varies inversely as the square of the distance. If you lived on a planet only half

sertanlavr [38]

Answer:

the intensity will be 4 times that of the earth.

Explanation:

let us assume the following:

intensity of light on earth =J

distance of earth from sun = d

intensity of light on other planet = K

distance of other planet from sun = $\frac{d}{2}$ (from the question, the planet is half as far from the sun as earth)

from the question the intensity is inversely proportional to the square of the distance, hence

intensity on earth : J = $\frac{1}{d^{2} }$

J $d^{2}$ = 1 ... equation 1

intensity on other planet : K = $\frac{1}{(\frac{d}{2}) ^{2} }$ (the planet is half as far from the sun as earth)

K $(\frac{d}{2}) ^{2}$ = 1 ....equation 2

equating both equation 1 and 2 we have

J $d^{2}$ = K $(\frac{d}{2}) ^{2}$

J $d^{2}$ = K $\frac{d^{2}}{4}$

J = $\frac{K}{4}$

K = 4J

intensity of light on other planet (K) = 4 times intensity of light on earth (J)

5 0

2 years ago

What is the average kinetic energy of an object's particles?

vova2212 [387]

What is the average kinetic energy of an object's particles?

the answer is temperature

7 0

1 year ago

Read 2 more answers

Two horizontal forces, 230 N and 120 N, are exerted in opposite direction on a crate. What is the horizontal acceleration of the

nignag [31]

Answer:

a = 5.5 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the force is equal to the product of mass by acceleration.

ΣF =m*a

where:

F = Force [N] (units of Newtons)

m = mass = 20 [kg]

a = acceleration [m/s²]

Let's take the force of 230 [N] as positive, in this way the other force will be negative, by pointing in the opposite direction.

$230 - 120 = 20*a\\110 = 20*a\\a=5.5 [m/s^{2} ]$

5 0

2 years ago

When a potential difference of 154 V is applied to the plates of a parallel-plate capacitor, the plates carry a surface charge d

tester [92]

Answer:

$4.7\mu m$

Explanation:

We are given that

Potential difference=V=154 V

Surface charge density= $\sigma=29nC/m^2=29\times 10^{-5} C/m^2$

Using $1 nC/cm^2=10^{-5} C/m^2$

We know that

$C=\frac{\epsilon_0A}{d}=\frac{Q}{V}=\frac{\sigma A}{V}$

$d=\frac{\epsilon_0V}{\sigma}$

Where

$\epsilon_0=8.85\times 10^{-12}C^2/Nm^2$

Using the formula

$d=\frac{8.85\times 10^{-12}\times 154}{29\times 10^{-5}}$

$d=4.7\times 10^{-6} m=4.7\mu m$

Using $1\mu m=10^{-6} m$

Hence, the spacing between the plates= $4.7\mu m$

3 0

2 years ago