Answer:
Explanation:
The velocity at the inlet and exit of the control volume are same 
Calculate the inlet and exit velocity of water jet

The conservation of mass equation of steady flow



since inlet and exit velocity of water jet are equal so the inlet and exit cross section area of the jet is equal
The expression for thickness of the jet

R is the radius
t is the thickness of the jet
D_j is the diameter of the inlet jet

(b)
![R-x=\rho(AV_r)[-(V_i)+(V_c)\cos 60^o]\\\\=\rho(V_j+V_c)A[-(V_i+V_c)+(V_i+V_c)\cos 60^o]\\\\=\rho(V_j+V_c)(\frac{\pi}{4}D_j^2 )[V_i+V_c](\cos60^o-1)]](https://tex.z-dn.net/?f=R-x%3D%5Crho%28AV_r%29%5B-%28V_i%29%2B%28V_c%29%5Ccos%2060%5Eo%5D%5C%5C%5C%5C%3D%5Crho%28V_j%2BV_c%29A%5B-%28V_i%2BV_c%29%2B%28V_i%2BV_c%29%5Ccos%2060%5Eo%5D%5C%5C%5C%5C%3D%5Crho%28V_j%2BV_c%29%28%5Cfrac%7B%5Cpi%7D%7B4%7DD_j%5E2%20%29%5BV_i%2BV_c%5D%28%5Ccos60%5Eo-1%29%5D)

![R_x=[1000\times(44)\frac{\pi}{4} (10\times10^{-3})^2[(44)(\cos60^o-1)]]\\\\=-7603N](https://tex.z-dn.net/?f=R_x%3D%5B1000%5Ctimes%2844%29%5Cfrac%7B%5Cpi%7D%7B4%7D%20%2810%5Ctimes10%5E%7B-3%7D%29%5E2%5B%2844%29%28%5Ccos60%5Eo-1%29%5D%5D%5C%5C%5C%5C%3D-7603N)
The negative sign indicate that the direction of the force will be in opposite direction of our assumption
Therefore, the horizontal force is -7603N
The force by which earth attracts anobject is know as weight of that particular object.
so,
=》weight ( F ) = mass ( M ) × acceleration ( A )
=》F = 85 × 9.8
( because acceleration due to gravity = 9.8, but sometimes it is taken as approx 10 )
=》F = 833 Newton.
note : if you take acceleration due to gravity as 10 then the weight of the person = 85 × 10 = 850 N )
i hope it helped.....
Her average speed would be 69.2 miles per hour
Explanation:
When you take the number of miles and divide it by the number of hours you get 69.2 (when rounded)
That is how fast she went per hour