Question

A merry-go-round at a playground is a circular platform that is mounted parallel to the ground and can rotate about an axis that is perpendicular to the platform at its center. The angular speed of the merry-go-round is constant, and a child at a distance of 1.4 m from the axis has a tangential speed of 2.2 m/s. What is the tangential speed of another child, who is located at a distance of 2.1 m from the axis?
(a) 1.5 m/s
(b) 3.3 m/s
(c) 2.2 m/s
(d) 5.0 m/s
(e) 0.98 m/s

Answer 1

Answer:

$V_2=3.3m/s$

Explanation:

From the question we are told that:

Distance $d_1=1.4m$

Tangential speed $V=2.2m/s$

Distance 2 $d_2=2.1m$

Generally the equation for Angular velocity is mathematically given by

 $w=\frac{v}{r}$

Therefore

 $\frac{v_1}{r_1}=\frac{v_2}{r_2}$

 $V_2=\frac{2.2*2.1}{1.4}$

 $V_2=3.3m/s$