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GuDViN [60]
3 years ago
6

What is the molar mass of Pb(SO4)2? Explain how you calculated this value.

Chemistry
1 answer:
solong [7]3 years ago
3 0
Hope this helps you!

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What volume is occupied by 35.2 g of carbon tetrachloride if its density is 1.60 g/ml?
ycow [4]

Density is mass divided by volume. Therefore, volume is mass divided by density.

V=\frac{m}{\rho}=\frac{35.2g}{1.60\frac{g}{ml}}=22.0\ ml

8 0
3 years ago
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A lab technician mixed a 550 ml solution of water and alcohol. if​ 3% of the solution is​ alcohol, how many milliliters of alcoh
kupik [55]

The solution 550 ml total and first we will find the amount of alcohol. 3% = 0.03 550 ml x .03 = 16.5 ml alcohol
 Then to find the amount of water used, we just have to subtract the amount of alcohol from the total volume  
550 ml total - 16.5 ml alcohol = 533.5 ml water
5 0
4 years ago
The rate constant for the decomposition reaction of H2O2 is 3.66 × 10−3 s−1 at a particular temperature. What is the concentrati
Pepsi [2]

Answer:  3.72 M

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant = 3.66\times 10^{-3}s^{-1}

t = age of sample = 15.0 minutes

a = let initial amount of the reactant  = 10.0 M

a - x = amount left after decay process = ?

15.0\times 60s=\frac{2.303}{3.66\times 10^{-3}}\log\frac{10.0}{(a-x)}

\log\frac{100}{(a-x)}=1.43

\frac{100}{(a-x)}=26.9

(a-x)=3.72M

The concentration of H_2O_2 in a solution after 15.0 minutes have passed is 3.72 M

7 0
3 years ago
Im the only noble gas with 2 electrons
iris [78.8K]

Answer:

Helium

Explanation:

8 0
3 years ago
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17. Which of the following describes a condition in which an individual would not hear an echo?
ivanzaharov [21]
<span>The right answer is D. In a situation where the sound wave reaches the ear and the reflected wave reaches the ear less than 0.1 seconds later, the individual would not be able to hear an echo. There needs to a far more significant delay between the sound and the reflection of said sound reaching the listener's ear for the echo effect to become apparent.</span>
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3 years ago
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