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melomori [17]
4 years ago
14

Calculate the percent composition for each of the elements in Na3PO4. A 5.00 gram sample of an oxide of lead PbxOy contains 4.33

g of lead. Determine the simplest formula for the compound. Balance the following equations by inspection: Cu(N03)2 rightarrow CuO + NO2 + O2 C2H6 + O2 rightarrow CO2 + H2O Mg3N2 + H2O rightarrow Mg(OH)2 + NH3 Magnesium (Mg) reacts with chlorine gas (C12) to produce magnesium chloride (MgC12). How many grams of Mg will react with 2 moles of Cl2? Mg(s) + C12(g) rightarrow MgC12(s) The compound P4S3 is used in matches. It reacts with oxygen to produce P4O10 and SO2. The unbalanced chemical equation is shown below, P4S3(s) + O2(g) rightarrow P4O10(s) + SO2(g) What mass of SO2 is produced from the combustion of 0.331 g P4S3 in excess O2? Nitric oxide is made from the oxidation of ammonia. What mass of nitric oxide can be made from the reaction of 8.00 g NH3 with 17.0 g O2? 4 NH3(g) + 5 O2(g) rightarrow 4 NO(g) + 6 H2O(g) To what volume should you dilute 50.0 mL of 12 M HNO3 solution to obtain a 0.100 M HNO3 solution?

Chemistry
1 answer:
Shkiper50 [21]4 years ago
6 0

Answer:

1. Percentage composition of: Na = 42%; P = 19.0%; O = 39%

2. Simplest formula of compound is PbO₂

3. (i) 2Cu(NO₃) ---> 2CuO + 2NO₂ + 3O₂

(ii) 2C₂H₆ + 7O₂ ---> 4CO₂ + 6H₂O

(iii) Mg₃N₂ + 6H₂O ---> 3Mg(OH)₂ + 2NH₃

4. 48 g of MG will react with 2 moles of Cl₂

5. 0.288 g of SO2 will be  produced from the combustion of 0.331 g P₄S₃ in excess O₂

6. 12.8 g of nitric oxide can be produced from the reaction of 8.00 g NH₃ with 17.0 g O₂

7. The stock acid solution should be diluted to 6000 mL or 6.0 L

Explanation:

The full explanation is found in the attachments below

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(CH3)2-CH-CH2-O(CH3)3IUPAC NAME
bazaltina [42]

Answer:

1-(tert-butoxy)-2-methylpropane

Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.

Explanation:

<em>Structural formula is attached</em>

IUPAC naming rules

1. start numbering the chain from the functional group. In this compound we        start from oxygen side.

2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.

3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.

4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane

5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane

3 0
4 years ago
an electric current causes water to be transformed into hydrogen and oxygen gasses a physical change or a chemical change
Natalija [7]
Physical change because ther is force which is the electric current
3 0
3 years ago
What are things that amorphous and crystalline have in common?
Juliette [100K]
Six brick land llwnswel
5 0
3 years ago
The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re
Kitty [74]

<u>Answer:</u> The temperature of the system will be 1622 K

<u>Explanation:</u>

The equation relating the pre-exponential factor and activation energy follows:

\log D=\log D_o-\frac{E_a}{2.303RT}

where,

D = diffusion coefficient = 2.7\times 10^{-14}m^2/s

D_o = pre-exponential constant = 1.7\times 10^{-5}m^2/s

E_a = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K

Hence, the temperature of the system will be 1622 K

8 0
3 years ago
How many atoms are present in 20.9 g of titanium
ZanzabumX [31]

Answer:

atoms Ti = 2.193 E23 atoms

Explanation:

  • 1 mol ≡ 6.022 E23 atoms
  • mm Ti = 47.867 g/mol

⇒ atoms Ti = (20.9 g Ti)×(mol/47.867 g)×(6.022 E23 atoms/mol)

⇒ atoms Ti = 2.193 E23 atoms

5 0
3 years ago
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