Well I don't know.
Let's think about it:
-- There are 6 possibilities for each role.
So 36 possibilities for 2 rolls.
Doesn't take us anywhere.
New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !
-- The die has 3 odds and 3 evens.
-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4
I'm sure this is it. I'm a little shaky on how to combine those 2 probs.
Ah hah !
Try this:
Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .
That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .
So the probability of 2 rolls that sum to an even number is 1/2 = 50% .
Is this reasonable, or sleazy ?
Answer:
Answer = 93.6
Step-by-step explanation:
frist multipy 9 x 13 to get 117 than divided it by 2 = 58.5, than times it by 3 since there is three sides.
(58.5 x 3 is 175.5)
Than for the base multipy 7.8 x 9 = 70.2, but since its a tri, divided it by 2 = 35.1.
Add 58.5 and 35.1 to get 93.6
Answer) That graph is not a function
Explanation) The graph that you provided is not a function. It does not pass the vertical line test. The vertical line test is when you draw a vertical line (l) at any point on the graph and it should touch 1 or less parts of the graph. If you put the line at x=1, the vertical line only touches the graph at (1,8.5) but if you put the line at x=5, it touches (5,1) and (5,8.5) so it does not pass the test. You should be able to put the line anywhere and have it touch ONLY 1 point. There cannot be multiple of the same x values.
Ok, so 11:9
11-9 = 2
which means that 124= 2:1
124/2 = 62
so 62:0
now 11 x 62= 682
9 x 62= 558
so the ratio is 682:558
now 682 + 558 = 1,240
There are 1,240 total students in the school. 682 boys and 558 girls
