In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=20.0 cm to x=60.0cm.
<h3>Where is the
electric potential, when the particle moved?</h3>
The charge field system's electric potential energy rose. The particle experiences an electric force that is directed against the x-axis. It is pushed uphill by an outside force, which raises the potential energy.
When a charge to be moved against an applied electric field, electric potential energy is needed. A charge must be moved through a stronger electric field with more energy than it would require to carry it via a weaker electric field.
In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=20.0 cm to x=60.0cm.
The electric potential energy of the charge field system:
- (a) increase
- (b) remain constant
- (c) decrease
- (d) change unpredictably
The correct option is a).
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Answer:
Explanation:
340 m/s / 968 cyc/s = 0.3512396... ≈ 35.1 cm
Answer:
(c) 10.29 J
(d) 113.19 J
(e) 113.19 J
(f) 10061 N/m
Explanation:
15 cm = 0.15 m
Let g = 9.8 m/s2
(c) The work done by gravitational force is the product of gravity force and the distance compressed
(d) By using law of energy conservation with potential energy reference being 0 at the maximum compression point. As the ball falls and come to a stop at the compression point, its potential energy is transferred to elastic energy, which is the work that the mattress does on the ball:
where h = 1.5 + 0.15 = 1.65 m is the vertical distance that it falls.
(e) Before the compression, the potential energy of the mattress is 0. After the compression, the potential energy is 113.19J. So it has increased by 113.19J due to the potential energy transferred from the falling ball.
(f) 
Explanation:
If g= 10m/s²
Then 75kg=75×10=750N
Since Work =Force ×Distance
Work=750×30
=22500J
And Power°=Work÷time
=22500÷120
=187.5W
Answer:
14.5m/s
Explanation:you had to divide 2.5s divide that by 1.8
