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aliya0001 [1]
3 years ago
8

A model car is 8 inches long. If it was built with a scale of 2 in. : 5 ft., then how long is the real car? (will give brainlies

t!!)
20 ft.

40 ft.

45 ft.

37 ft.
Mathematics
1 answer:
serious [3.7K]3 years ago
7 0
The real car would be 20ft
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Jim Panzee got in a taxi that charges a $10 flat fee plus $3 per mile traveled. Write an equation that shows the relationship be
nekit [7.7K]

Answer:

the total is $25 for a 5 mile ride.

the total is $40 for a 10 mile ride.

Step-by-step explanation:

x*3+y= total

5*3=$15

$15+$10=$25

10*3=$30

$30+$10=$40

8 0
3 years ago
Which of the following is the equation for the line perpendicular to the line y= -x + 20 that passes through the point (-4, 2)?
Nadya [2.5K]

Answer:

Step-by-step explanation:

A 10= 4 plus 6

7 0
3 years ago
-what is the answer<br>​
faust18 [17]

Answer:

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Step-by-step explanation:

4 0
2 years ago
How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove
BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

\dfrac{9}{n^2+1} =\dfrac{n+3}{4}

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\

The roots (zeros) are the  x  values where the graph intersects the x-axis. To find the roots (zeros), replace  y

with  0  and solve for  x. The graph of the equation is attached.

n  ≈  2.38450287

Hence, The equation has one extraneous solution which is n  ≈  2.38450287

For more information refer to the link.

brainly.com/question/15070282

5 0
2 years ago
Is 48 a perfect cube? Explain your reasoning.
Ksivusya [100]

Answer:

No

Reasoning:

If something is a perfect cube, it is able to be put under a cube root (\sqrt[3]{..}) and will result in an integer (a non-decimal number > 0, basically).

So let's calculate \sqrt[3]{48}, and see if the result is an integer.

\sqrt[3]{48} = 3.634.......

As you can see, the result is not an integer, therefore 48 is not a perfect cube.

8 0
2 years ago
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