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Reil [10]
3 years ago
7

Some advocates of anabolic steroid use report that testicular atrophy associated with use of trenbolone can be alleviated if use

rs also inject themselves with human chorionic gonadotropin, a hormone similar in structure and function to LH and FSH. Please explain how this treatment might work.
Chemistry
1 answer:
skelet666 [1.2K]3 years ago
8 0

Answer:

Human chorionic gonadotropin (HCG) injections are much safer to use with some mild side effects to treat issues of testicular atrophy. Human chorionic gonadotropin (HCG) injections would increase blood flow and enable the testes' produce testosterone, reduce the shrinkage of the testicles and it also aids in the production of sperm cells which has been initially impaired due to testicular atrophy.

Explanation:

Anabolic steroid is a drug that plays the role of testosterone.

Testicular atrophy is the shrinkage of the testicles caused by old age or infections. Once it occurs, it lowers the production of testosterone and sperm cells.

Trenbolone increases muscle building, aids lean fat deposition, reduces the production of testosterone, and could also lead to testicular atrophy.

You might be interested in
How does water change the shape of Earth's surface?
xz_007 [3.2K]

Answer:

Water moving across the earth in streams and rivers pushes along soil and breaks down pieces of rock in a process called erosion. The moving water carries away rock and soil from some areas and deposits them in other areas, creating new landforms or changing the course of a stream or river.

Explanation:

5 0
3 years ago
Read 2 more answers
Liquid octane CH3CH26CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O . Suppose
Slav-nsk [51]

Answer:

The minimum mass of octane that could be left over is 43.0 grams

Explanation:

Step 1: Data given

Mass of octane = 73.0 grams

Mass of oxygen = 105.0 grams

Molar mass octane = 114.23 g/mol

Molar mass oxygen = 32.0 g/mol

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate the number of moles

Moles = mass / molar mass

Moles octane = 73.0 grams / 114.23 g/mol

Moles octane = 0.639 moles

Moles O2 = 105.0 grams / 32.0 g/mol

Moles O2 = 3.28 moles

Step 4: Calculate the limiting reactant

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

O2 is the limiting reactant. It will completely be consumed. (3.28 moles). There will react 3.28 / 12.5 = 0.2624 moles. There will remain 0.639 - 0.2624  = 0.3766 moles octane

Step 5: Calculate mass octane remaining

Mass octane = moles * molar mass

Mass octane = 0.3766 moles * 114.23 g/mol

Mass octane = 43.0 grams

The minimum mass of octane that could be left over is 43.0 grams

3 0
3 years ago
A basketball weighs approximately 1.35 kg. What is this mass in grams (g)?<br><br> step by step
choli [55]

Answer:

1350 g

Explanation: just add a 0

8 0
3 years ago
How many atoms (mol) is in 10g of sodium, sodium chloride and Iron chloride?
SashulF [63]

Answer:

See explanation

Explanation:

Molar mass of NaCl = 58.5 g

Number of moles contained in 10 g of NaCl = 10 g/58.5 g = 0.17 moles

If 1 mole of NaCl contains 6.02 * 10^23 atoms

0.17 moles of NaCl contains 0.17 * 6.02 * 10^23 atoms = 1.02 * 10^23 atoms

Molar mass of Fe II chloride = 126.751 g/mol

Number of moles = 10 g/126.751 g/mol = 0.0789 moles

Number of atoms = 0.0789 moles *  6.02 * 10^23 atoms = 4.7 * 10^22 atoms

Molar mass of Na = 23 g/mol

Number of moles = 10g/23 g/mol = 0.43 moles

Number of atoms = 0.43 moles *  6.02 * 10^23 atoms = 2.59 * 10^ 23 atoms

8 0
3 years ago
Balance the following equation in acidic conditions. Phases are optional.
NISA [10]
I think the reaction involved here is a redox reaction in acidic conditions. To balance this type of reaction, we do as follows:

Balance the O atoms in each side by adding H2O on either side.
Balance H atoms in each side by adding H+.
Balance the charges by adding electrons.

Hope this helps.
4 0
4 years ago
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