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ElenaW [278]
2 years ago
9

A basketball weighs approximately 1.35 kg. What is this mass in grams (g)? step by step

Chemistry
1 answer:
choli [55]2 years ago
8 0

Answer:

1350 g

Explanation: just add a 0

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Which SI unit would be most appropriate for expressing the mass of this animal
Ede4ka [16]

Answer:

Kilograms, I think.

Explanation:

8 0
2 years ago
Is a strong acid<br> a. NaC₂H₃O₂ <br> b. HC₂H₃O₂<br> c. KCl <br> d. NH₃<br> e. HCl
sammy [17]
E. HCI

Source:
The Internet
7 0
2 years ago
The sulfuric acid–catalyzed reaction of isopentyl alcohol with acetic acid to form isopentyl acetate is performed. This reaction
murzikaleks [220]

Answer:

The correct option is acetic acid

Explanation:

Distillation is the process of separating a mixture of substances based on differences in boiling points. During distillation, the compound with the lowest/least boiling point is distilled and collected first and then the one with the next least boiling point and it goes on like that.

From the explanation above, <u>acetic acid has the least boiling point (in the organic layer) with 118°C and thus will distill first</u>. This is then followed by isopentyl alcohol (130°C) and then isopentyl acetate (142°C) and finally sulfuric acid water (290°C).

6 0
2 years ago
Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction entropy of the following chemical rea
Aleksandr [31]

Answer:

ΔS° = - 47.2 J/mol.K

Explanation:

  • P4O10 + 6H2O → 4H3PO4

ΔS°= 4(S°mH3PO4) - 6(S°mH2O) - S°mP4O10

∴ S°mH2O(l) = 69.9 J/mol.K

∴ S°mP4O10 = 231 J/mol.K

∴ S°mH3PO4 = 150.8 J/mol.K

⇒ ΔS° = 4*(150.8) - 6*(69.9) - 231

⇒ ΔS° = - 47.2 J/mol.K

5 0
2 years ago
Read 2 more answers
What is the pressure of 1.50 moles of a gas in a 30.0L tank at a temperature of<br> 285K?
julia-pushkina [17]

The pressure of the gas : 1.1685 atm

<h3>Further explanation</h3>

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

n=moles=1.5

V=volumes = 30 L

T=temperature=285 K

The pressure :

\tt P=\dfrac{nRT}{V}\\\\n=\dfrac{1.5\times 0.082\times 285}{30}\\\\P=1.1685~atm

7 0
2 years ago
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