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3 years ago

How do I change my name on brainly? I'm on my phone

Mathematics

1 answer:

I am Lyosha [343]3 years ago

3 0

Answer:

you just so to your account settings and then you just go to preferences and it will show you the option to change your name

Step-by-step explanation:

You might be interested in

If you were going to represent the top view of the figure, state which boxes should be shaded. Write an essay. Pls, help. Thx.

Rudiy27

Answer:

9, 13, 10, 11, 7, 3, 4.

Step-by-step explanation:

9, 13, 10, 11, 7, 3, 4 are the ones which should be shaded and can be seen from the top. In ascending order: 3, 4, 7, 9, 10, 11, 13.

1, 2, 5, 6, 8, 12, 16, 14, 15 are the numbers of the boxes that would not be seen from the top.

Hope this helps!

4 0

3 years ago

Read 2 more answers

Two numbers have a sum of 117 and a difference of 43. Find the numbers.

blondinia [14]

Answer:

this kid grayson is deleting my answer and i dont know how when they arent even his questions and he is being a little brat

Step-by-step explanation:

so watch out for him

6 0

3 years ago

Read 2 more answers

Order: Anadrol-50 (oxymetholone) 200 mg po daily. The recomnes patient who has bipolar disorder? 3 kg 50 e ste for Is the prescr

VMariaS [17]

Answer:

Yes the ordered dose of 200 mg/d lies within the recommended range of 75 mg/d to 375 mg/d

Step-by-step explanation:

Given:

Ordered dose of Anadrol-50 (oxymetholone) = 200 mg per day

Recommended range = 1-5 mg/kg/d

Weight of the patient = 75 kg

Now,

For the patient weighing 75 kg, the recommended dose will be

Minimum dose will be

= Minimum value of Recommended range × Weight of the patient

= 1 mg/kg/d × 75 kg

= 75 mg/d

and,

the Maximum dose will be

= Maximum value of Recommended range × Weight of the patient

= 5 mg/kg/d × 75 kg

= 375 mg/d

Yes the ordered dose of 200 mg/d lies within the recommended range of 75 mg/d to 375 mg/d

4 0

3 years ago

Can somebody please help me with this question?

kompoz [17]

Answer:

Step-by-step explanation:

Solve the first half of the equation-

-8x+3 >/=27

-3 -3

-8x>/=24

divided by -8 on both sides

x</=-3

Now for the second side:

-13x+5>/= 57

-5 -5

-13x>/=52

divide by -13 in both sides

x</=-4

We now have two equations. The answer would be x</=-3 because -4 is also less than three, so it can be simplified down to -3. I know you might not have needed the explanation since it’s just khan academy, but I figured I’d explain it anyway :)

4 0

3 years ago

The probability of winning on a single toss of the dice is p. A starts, and if he fails, he passes the dice to B, who then attem

alekssr [168]

Answer:

The probability of A winning is $\frac{1}{2-p}$ and the probability of B winning is $\frac{1-p}{2-p}$ .

Step-by-step explanation:

The probability of winning is p.

The game stops when either A or B wins.

The sample space of A winning is as follows:

{S, FFS, FFFFS, FFFFFFS, ...}

The sample space of B winning is as follows:

{FS, FFFS, FFFFFS, FFFFFFFS, ...}

Compute the probability of A winning as follows:

P (A winning) = P (S) + P (FFS) + P (FFFFS) + ...

$=p+(1-p)(1-p)p+(1-p)(1-p)(1-p)(1-p)p+...\\=p\sum\limits^{\infty}_{i=0} {(1-p)^{2i}}\\=p\times \frac{1}{1-(1-p)^{2}}\\=\frac{p}{1-(1-p)^{2}}\\=\frac{p}{1-1-p^{2}+2p}\\=\frac{1}{2-p}$

Compute the probability of B winning as follows:

P (B winning) = P (FS) + P (FFFS) + P (FFFFFS) + ...

$=(1-p)p+(1-p)(1-p)(1-p)p+(1-p)(1-p)(1-p)(1-p)(1-p)p+...\\=(1-p)p\sum\limits^{\infty}_{i=0} {(1-p)^{2i}}\\=(1-p)p\times \frac{1}{1-(1-p)^{2}}\\=\frac{(1-p)p}{1-(1-p)^{2}}\\=\frac{(1-p)p}{1-1-p^{2}+2p}\\=\frac{1-p}{2-p}$

Thus, the probability of A winning is $\frac{1}{2-p}$ and the probability of B winning is $\frac{1-p}{2-p}$ .

3 0

3 years ago