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Monica [59]
3 years ago
15

Help help help help help help help help help help please!!! worth 20 points please helppppp!!!!

Chemistry
1 answer:
kvasek [131]3 years ago
4 0

Explanation:

here

Al is 2

so is 6

and more you can do it

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Write the empirical formula for at least four ionic compounds that could be formed from the following ions:
love history [14]

Answer:

FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}

Explanation:

Empirical formula of ionic compound formed by two ions A^{x+} and B^{y-} is A_{y}B_{x} (for x\neq y) of AB (for x = y)

The above empirical formula is in accordance with charge neutrality principle

Here each cation (Fe^{3+} and Fe^{2+}) can form two ionic compounds by combining with two given anions (SO_{4}^{2-} and CH_{3}CO^{2-}).

So the four ionic compounds are: FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}

4 0
4 years ago
Given 6 moles of CuCl2, how many moles of AlCl, were made? SHOW the math below​
Anastasy [175]

Answer:

6 moles of CuCl₂  will produced 4 moles of  AlCl₃ .

Explanation:

Given data:

Moles of CuCl₂ = 6 mole

Moles of AlCl₃ produced = ?

Solution:

3CuCl₂ + 2Al → 2AlCl₃ + 3Cu

Now we will compare the moles of CuCl₂ with AlCl₃ .

            CuCl₂        :        AlCl₃

                3            :          2

                6           :         2/3 ×6 = 4 mol

So, 6 moles of CuCl₂  will produced 4 moles of  AlCl₃ .

6 0
3 years ago
Natural remedies are usually more effective and safer because they have thoroughly tested .
mihalych1998 [28]
The answer for this question would be B) False or the second option.

Answer is FALSE: ✅
6 0
3 years ago
HELP ASAP PLEASE<br> Use the word Precision in a sentence relating to chemistry!
Leno4ka [110]

Answer:

I needed to use good precision in my measurement for my chemistry lab

Explanation:

7 0
3 years ago
A diver has a lung capacity of 2.4 L when the pressure is 0.8 atm. What is the volume of the diver’s lungs when the pressure cha
tangare [24]

Answer:

The final volume is 1.6 L.

Explanation:

It is given that,

A diver has a lung capacity of 2.4 L when the pressure is 0.8 atm. We need to find the volume of the diver’s lungs when the pressure changes to 1.2 atm. Let V₂ is volume.

It is based on Boyle's law. According to this law,

PV=K

K is constant

P_1V_1=P_2V_2

V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{0.8\times 2.4}{1.2}\\\\V_2=1.6\ L

So, the final volume is 1.6 L.

7 0
3 years ago
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