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ankoles [38]
3 years ago
5

Which is the most important part of the food web? Producers, decomposers, carnivores, or herbivores

Chemistry
2 answers:
mash [69]3 years ago
8 0

Answer:

all is important

Explanation:

goldfiish [28.3K]3 years ago
4 0

Answer:

All parts of the food chain are very important for if one is part of the food chain is tooken away than other parts of the food chain will be affected.

Explanation:

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According to Bohr atomic model
nata0808 [166]

Answer:

A small positively charged nucleus surrounded by revolving negatively charged electrons in fixed orbits

7 0
3 years ago
How many molecules of carbon dioxide, CO2, are present in 388.1 grams?
swat32

Answer:

53.11× 10²³ molecules

Explanation:

Given data:

Number of molecules of CO₂ = ?

Mass of CO₂ = 388.1 g

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of CO₂ = 12× 1 + 16×2

Molar mass of CO₂ = 44 g/mol

Now we will put the values in formula.

Number of moles = 388.1 g/ 44 g/mol

Number of moles = 8.82 moles

Now we will calculate the number of molecules by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

8.82 mol × 6.022 × 10²³ molecules / 1 mol

53.11× 10²³ molecules

6 0
2 years ago
Bonds between metals and nonmetals tend to be ionic, but bonds between nonmetal atoms tend to be covalent.
I am Lyosha [343]
O i get it it does not stik on metal eater way
5 0
3 years ago
Read 2 more answers
How do I balance a chemical reaction like one of these NaBr + Ca(OH)2 ➡️ CaBr2 + NaOH
mojhsa [17]
2NaBr + Ca(OH)2 ➡️ CaBr2 + 2NaOH
3 0
3 years ago
1. If a solution containing 48.99 g of mercury(II) perchlorate is allowed to react completely with a solution containing 8.564 g
Vitek1552 [10]

1. Chemical eqn:

Hg(ClO4)2 + Na2S -> HgS + 2NaClO4

mercury perchlorate has a molar mass of 399.5g/mol (1d.p) and for Na2S it is 78.0g/mol (1d.p.)

no. of moles of mercury perchlorate= 48.99÷399.5= 0.12263mol(5s.f.)

no. of moles of Na2S= 8.564÷78.0= 0.10979mol ( 5s.f.)

so no. of moles of Hg(ClO4)2/ no. of moles of Na2S= 1/1 according to the eqn

so no. of moles of Hg(ClO4)2 needed if all Na2S is used up is 1/1×0.10979= 0.10979 mols

since no. of moles of mercury perchlorate needed < no. of moles of it provided, it is in excess and Na2S is the limiting factor.

since HgS is a solid and NaClO4 is aqueous, solid ppt formed will only be HgS.

no. of moles of HgS/ no. of moles of NaClO4= 1/1

no. of moles of HgS produced= 0.10979mols

molar mass of HgS= 232.7g/mol 1d.p.

grams of solid produced= 232.7×0.10979= 25.5g (3s.f.)

2. reactant in excess is Hg(ClO4)2,

no. of excess moles= 0.12263-0.10979= 0.01284mols

grams of excess reactant= 0.01284×399.5= 5.13g (3s.f.)

3 0
3 years ago
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