How many atoms are in 2.56 g of Si?

What is the density if a sample of rock has a mass of 69 g and a volume of 23 ml?

kiruha [24]

Density = mass / volume

= 69g / 23 ml

= 3 g / ml.

Thus, the density of the sample is 3 grams per ml or 3g/ ml

4 0

4 years ago

What is temperature? How do we measure temperature? What temperature unit were you supposed to record in the layers of the earth

OLga [1]

=The measure of warm and coldness of an object or substances with references to some standard value is known as temperature.

= We measure temperature by Fahrenheit (°F) scale, the Kelvin (K), and the Celsius (°C).

8 0

3 years ago

The most stable conformation of trans-1-tert-butyl-2-methylcyclohexane is the one in which:

Margaret [11]

The most stable conformation of trans-1-tert-butyl-2-methylcyclohexane is the one in which both the tert-butyl group and the methyl group are located near the equatorial position. Trans conformation are usually stable at the equatorial position to avoid the bulkyl group ( the tert-butyl group and methyl group) be together to reduce the so called Steric hindrance.

4 0

3 years ago

The balanced chemical equation for the reaction of copper (Cu) and silver nitrate (AgNO3) is shown below. Cu + 2AgNO3 mc001-1.jp

sergij07 [2.7K]

The balanced reaction is:

Cu + 2AgNO3 = 2Ag + Cu(NO3)2

We are givent the amount of silver to be produced. This will be the starting point. Calculations are as follows:

 3.50 mol Ag ( 1 mol Cu / 2 mol Ag ) = 1.75 mol Cu

Therefore, we need 1.75 mol of copper in order to produce 3.50 mol of silver.

8 0

3 years ago

Read 2 more answers

To determine the molecular weights of the acid, a student dissolved a pure sample (400.0 mg) in a water to a total volume of 100

klasskru [66]

Answer:

83.86g/mol is the molecular weight of the acid

Explanation:

Molecular weight is the ratio of mass in grams and moles present. That means we need to determine the mass in grams (400.0mg = 0.400g) and the moles of the acid that can be detemined by using its reaction with NaOH:

Moles acid:

First, we need to assume the acid is a monoprotic acid (Only 1 proton is acid and reacts with a base).

when the acid, HX, reacts with NaOH there is produced:

HX + NaOH → H₂O + NaX

Where 1 mole of HX reacts per mole of NaOH. That means the moles at the endpoint of NaOH = Moles of HX:

Moles NaOH:

15.90mL= 0.01590L * (0.0750mol / L) = 1.193x10⁻³ moles of NaOH = Moles of HX are present.

The acidic solution was diluted to 100.0mL but only 25.00mL were taken, that is:

25.00mL / 100.00mL = 1/4 of the acid was titrated.

And moles of HX in the original solution are:

1.193x10⁻³ moles of HX * 4 = 4.77x10⁻³ moles of HX

It is multiplied by 4 because the real amount of acid is 4 times the titrated amount.

Thus, molecular weight is:

0.4000g / 4.77x10⁻³ moles of HX =

<h3>83.86g/mol is the molecular weight of the acid</h3>

8 0

3 years ago