Answer / Explanation:
Referencing the diagram of a resonance in a vertical tube as illustrated in the attached diagram below,
we can say that:
Vertical wave is the result of superposition of dual and identical waves.
We should also note that the only difference is that they travel in opposite directions to each other.
So, let assume a tuning fork is vibrated with frequency ν
at the open end of the tube of varying length which can be changed during vibration with the help of water level change.
Also, let us assume the minimum length of the tube be L, when the resonance is heard.
Also, we assume that 1/4 of the wavelength λ
of the standing wave is equal to length of the minimum length L of the tube.
Hence, we have:
λ = 4
L
.
So, if speed of sound in air is V
, then frequency of the tuning fork can be expressed as:
U = v / λ = v / 4L
Noting that we have been given the speed of sound in air as V = 343
m
/
s
.
where:
U = v / λ = v / 4L
therefore,
343
m
/
s / 4 x 0.5525 m
= 155.20 Hz
Noting that 1 wave length in centimeter is 29979245800 Hz
Therefore, I wavelength in centimeter = 29979245800 Hz / 155.20 Hz
= 193 cm
<span>A large body of air hats has similar properties of a temperature and moisture is an air mass.</span>
Answer:
1) Potential energy of the ball just before the kick was taken = 0J
2) The potential energy of the ball just before it was caught = 58.8 J
Explanation:
1)Since the height of the ball is 0m on the ground, the potential energy of the ball just before the kick was taken is 0 J
2) The mass of the ball, m = 1.5 kg
Acceleration due to gravity, g = 9.8 m/s^2
the height of the ball, h = 4 m
The Potential Energy = mgh
The potential energy of the ball just before it was caught = 1.5 x 9.8 x 4
The potential energy of the ball just before it was caught = 58.8 J
From the planks equation
E=hv
V= c/ wave length
V= 3×10^8/30×10^-9
=1×10^16
E= hv
6.63×10^-34×1×10^16
= 6.63×10^-18
Answer:
spring constant of the spring is 1820.44 N/m
Explanation:
given data
ball mass = 4 kg
speed = 16 m/s
distance = 0.75 m
to find out
spring constant of the spring
solution
we know that kinetic energy of ball = energy store in spring as compression
so we can express it as
0.5 × m × v² = 0.5 × k × x² ....................1
so put here value we get spring constant k
m × v² = k × x²
4 × 16² = k × 0.75²
solve it we get
k = 1820.44 N/m
so spring constant of the spring is 1820.44 N/m