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makvit [3.9K]
3 years ago
8

Gli iceberg nel Nord Atlantico rappresentano un rischio per la navigazione, costringendo ad allungare le rotte di navigazione di

circa il 30% durante la stagione della loro presenza. I tentativi per distruggere gli iceberg comprendono l’inserimento di esplosivi, bombardamenti, siluramenti, speronamenti, rivestimenti con fuliggine nera. Supponete che si sia provato a fondere direttamente l’iceberg, ponendo delle sorgenti calde nel ghiaccio.
Quanto calore è necessario per fondere il 10% di un iceberg da 200 000 tonnellate?
Scrivere il calcolo per esteso, non solo risultato numerico.
Physics
1 answer:
nikklg [1K]3 years ago
6 0

I DONT UNDERSTND IS ANOTHER LANGUAGR

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A cylinder which is in a horizontal position contains an unknown noble gas at 4.63 × 104 Pa and is sealed with a massless piston
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Answer:

The change in internal energy of the system is -17746.78 J

Explanation:

Given that,

Pressure P=4.63\times10^{4}\ Pa

Remove heat \Delta U= -1.95\times10^{4}\ J

Radius = 0.272 m

Distance d = 0.163 m

We need to calculate the internal energy

Using thermodynamics first equation

dU=Q-W...(I)

Where, dU = internal energy

Q = heat

W = work done

Put the value of W in equation (I)

dU=Q-PdV

Where, W = PdV

Put the value in the equation

dU=-1.95\times10^{4}-(4.63\times10^{4}\times3.14\times(0.272)^2\times(-0.163))

dU=-17746.78\ J

Hence, The change in internal energy of the system is -17746.78 J

3 0
3 years ago
If the average pitcher is releasing the ball from a height of 1.8 m above the ground, and the pitcher's mound is 0.2 m higher th
mina [271]

The catcher can catch the ball at a height of 0.96 m from the ground.

The distance between the pitcher's mound and the catcher's box is about 60'6", which translates to 18.44 m. An average pitcher can pitch with speeds ranging from 88 mph to 97 mph, which is from 39.3 m/s to 43.4 m/s.

Assume the pitcher pitches a ball horizontally with a speed of 40 m/s. If the catcher catches the ball in a time t, then the ball travels a horizontal distance x of 18.44 m and at the same time falls through a height y.

The horizontal motion of the ball is uniform motion since no force acts on the ball ( assuming no air resistance) and hence the acceleration of the ball along the horizontal direction is zero.

Therefore,

x=ut

Calculate the time t by substituting 18.44 m for x and 40 m/s for u.

t=\frac{x}{u} \\ =\frac{18.44 m}{40 m/s} \\ =0.461s

The ball is acted upon by the earth's gravitational attraction and hence it accelerates downwards with an acceleration equal to the acceleration due to gravity g.

Since a horizontal projection is assumed, the ball has no component of velocity in the downward direction.

Therefore, for vertical motion, which is an accelerated motion, the distance y, the ball falls in the time t taken by it to reach the catcher's box is given by the equation,

y=\frac{1}{2} gt^2

Substitute 9.8 m/s² for g and 0.461 s for t.

y=\frac{1}{2} gt^2\\ y=\frac{1}{2}(9.8 m/s^2)(0.461s)^2=1.04 m

The pitcher releases the ball at a height of 1.8 m from a mound which is at a height of 0.2 m. Thus, the ball is released at a height of 2.0 m from the ground. It falls through a distance of 1.04 m in the time it takes to reach the catcher.

Therefore, the height at which the catcher needs to keep his glove so as to catch the ball is given by,(2.0 m)-(1.04 m)=0.96 m

The catcher needs to hold his glove at a height of <u>0,96 m from the ground.</u>

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What information did the movement of the bubble over a specified distance in the calibrated respirometer provide
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The following explanatory section gives an explanation of this question.

Explanation:

  • This means that perhaps the bubble moves more than a certain duration throughout the calibration breath meter offers the rate as well as oxygenation consumed inside this cell.
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In the forest (phrase—noun, but no subject and no verb) Smashing against the bat (phrase—verb but no subject) Before our first c
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