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maw [93]
3 years ago
5

You are a traffic accident investigator. You have arrived at the scene of an accident. Two cars of equal mass (1,000 kg each) we

re involved in a rear-end accident at a stop sign. Here is what you know: Car 1 approached the intersection from the top of a 25-meter hill. Car 2 was on a flat stretch of road directly in front of Car 1. At the bottom of the hill, Car 1 was going 20 m/s; Car 2 was going 30 m/s before it stopped at the stop sign. There were no skid marks left by Car 2. The collision occurred at the stop sign, where Car 2 had stopped. After the collision, both cars were moving together in the same direction at 10 m/s before slowly rolling to a stop. You must now push Car 2, using 800 N of force, 10 meters off to the side of the road so no one else gets hurt.
1. What was the potential energy of Car 1 at the top of the hill? (3 points)




2. What was the kinetic energy of each car before braking? (4 points)




3. A. How much energy did Car 1 lose from the top to the bottom of the hill? (3 points)




B. Where do you suppose that energy went? (2 points)




4. How much work was done to bring Car 2 to a stop? (4 points)




5. If Car 2 came to a stop in 15 seconds, how much power (in watts) did it take to stop Car 2 at the stop sign by applying force to the brakes? (3 points)




6. What is the final combined momentum of the cars right after the accident? (6 points)




7. Assuming that there are no other nonconservative forces involved, what impulse was given to each car during the collision? (6 points)
A. Car 1 (3 points)




B. Car 2 (3 points)




8. How much energy did Car 1 lose in the collision? (3 points)




9. How much energy did Car 2 gain in the collision? (3 points)




10. Which of the two laws covered in this unit - Law of Conservation of Momentum or Law of Conservation of Energy - is obeyed in this problem? Explain your reasoning. (5 points)




11. How much work did it take to move Car 2 off to the side of the road? (3 points)




12. If it took you 40 seconds to move Car 2 off the road, how much power did you expend? (3 points)




13. Which simple machine does a car have that helped you move Car 2? Explain. (2 points)
Physics
1 answer:
kumpel [21]3 years ago
4 0
6. Is 50 m/s that’s the answer
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1) Any particle moving in a horizontal plane slowed by friction, deceleration = 32 μ

2) The particle moving by acceleration = P/m - 32μ OR The external force = ma + 32μm

Explanation:

* Lets revise Newton’s Third Law:

- For every action there is a reaction, equal in magnitude and opposite

 in direction.

- Examples:

# 1) A particle moving freely against friction in a horizontal plane

- When no external forces acts on the particle, then its equation of

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∵ ∑ forces in direction of motion = mass × acceleration

∵ No external force

∵ The friction force (F) = μR, where μ is coefficient of the frictional force

   and R is the normal reaction of the weight of the particle on the

   surface

∵ The frictional force is in opposite direction of the motion

∴ ∑ forces in the direction of motion = 0 - F

∴ 0 - F = mass × acceleration

- Substitute F by μR

∴ - μR = mass × acceleration

∵ R = mg where m is the mass of the particle and g is the acceleration

  of gravity

∴ - μ(mg) = ma ⇒ a is the acceleration of motion

- By divide both sides by m

∴ - μ(g) = a

∵ The acceleration of gravity ≅ 32 feet/sec²

∴ a = - 32 μ

* Any particle moving in a horizontal plane slowed by friction,

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# 2) A particle moving under the action of an external force P in a

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- When an external force P acts on the particle, then its equation

 of motion is;

∵ ∑ forces in direction of motion = mass × acceleration

∵ The external force = P

∵ The friction force (F) = μR, where μ is coefficient of the frictional force

   and R is the normal reaction of the weight of the particle on the

   surface

∵ The frictional force is in opposite direction of the motion

∴ ∑ forces in the direction of motion = P - F

∴ P - F = mass × acceleration

- Substitute F by μR

∴ P - μR = mass × acceleration

∵ R = mg where m is the mass of the particle and g is the acceleration

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∵ The acceleration of gravity ≅ 32 feet/sec²

∴ P - 32μm = ma ⇒ (1)

- divide both side by m

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∴ a = P/m - 32μ

* The particle moving by acceleration = P/m - 32μ

- If you want to fin the external force P use equation (1)

∵ P - 32μm = ma ⇒ add 32μm to both sides

∴ P = ma + 32μm

* The external force = ma + 32μm

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