Heya!!
For calculate final velocity, lets applicate formula
<u>Δ Being Δ</u>
V = Final Velocity = ?
Vo = Initial velocity = 0 m/s
a = Aceleration = 5 m/s²
t = Time = 12 s
⇒ Let's replace according the formula:
⇒ Resolving
Result:
The velocity after 10 sec is <u>60 meters per second (m/s)</u>
Good Luck!!
The ratio of intensity to distance is an inverse square law so if you increase the distance by 3 times, the intensity will reduce by
times
so the intensity will be 9 times less.
Answer:
E ’= E / 8
therefore the correct answer is A
Explanation:
Let's calculate the electric field in an insulating sphere with a radius r <R, let's use Gauus's law, with a spherical Gaussian surface
Фi = ∫ E. dA = /ε₀
E (4πr²) = q_{int} / ε₀
density is
ρ = q_{int} / V
q_{int} = ρ V = ρ 4/3 π r³
we substitute
E (4π r²) = ρ 4/3 π r³ /ε₀
E = 1 /3ε₀ ρ r
let's change the density by
ρ = Q / V = Q / (4/3 π R³)
E = 1 / 4πε₀ Q r / R³
if we now distribute the same charge on a sphere of radius R' = 2R
E ’= 1 / 4pieo Q r / (2R)³
E ’= 1 / 4ft Qr / R³ ⅛
E ’= E / 8
therefore the correct answer is A
Answer:
-1.4N
Explanation:
When the distance between A and B is 13.8mm (0.0138m), the force exerted by A on B is 2.65N:
F(A,B) = k*qA*qB/r²
=> 2.65 = k*qA*qB / 0.0138²
=> k*qA*qB = 2.65 * 0.0138²
k*qA*qB = 0.0005046
When the distance between them increases to 19mm (0.019m), the force exerted by A on B becomes:
F(A,B) = k*qA*qB / 0.019²
Given that k*qA*qB = 0.0005046,
F(A,B) = 0.0005046/0.019²
F(A,B) = 1.4N
The force exerted by B on A will be in the opposite direction of the force exerted by A on B, which means that the force exerted by B on A will be:
F(B, A) = -1.4N