Answer:
the period T of whole motion should be twice the value for half at he bottom so T is 0.2sec.
w is angular frequency
formula:2π/T
now k is spring constant
F/R-->mw²
putting values:70*(2π/0.2)²
=4.9x10⁶
so we can say that SHM is not affected by the amplitude of the bounce.
Lighter molecules move fast and escape from the upper atmosphere relatively quickly.
To find the answer, we have to know more about the lighter isotopes.
<h3>
What are lighter isotopes?</h3>
- Lighter molecules are mobile and soon leave the higher atmosphere.
- A particular element's stable isotopes have slightly different atomic masses and quantum mechanical energies.
- The lighter isotope of an element's chemical bonds are more easily broken than the heavier isotope's.
- As a result, the light isotope typically benefits from chemical reactions.
Thus, we can conclude that, lighter molecules move fast and escape from the upper atmosphere relatively quickly.
Learn more about the isotopes here:
brainly.com/question/364529
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Answer:
Explanation:
Let v be the velocity acquired by electron in electric field
V q = 1/2 m v²
V is potential difference applied on charge q , m is mass of charge , v is velocity acquired
2400 x 1.6 x 10⁻¹⁹ = .5 x 9.1 x 10⁻³¹ x v²
v² = 844 x 10¹²
v = 29.05 x 10⁶ m /s
Maximum force will be exerted on moving electron when it moves perpendicular to magnetic field .
Maximum force = Bqv , where B is magnetic field , q is charge on electron and v is velocity of electron
= 1.7 x 1.6 x 10⁻¹⁹ x 29.05 x 10⁶
= 79.02 x 10⁻¹³ N .
Minimum force will be zero when electron moves along the direction of magnetic field .
As momentum / time = force
so; time = 100÷15
so your answer is 6.7 !!
