An equation showing the relationship between the THREE forces is R -W +F= 0
<h3>What is moment of force?</h3>
The equal and opposite force acting at a point from the axis of rotation is called the moment of force.
M = F x r
Given is a wheelbarrow and stones with a total mass of 43 kg. The wheelbarrow is in equilibrium with two of the three forces acting on it
Taking moment about the wheel, we get
-43x 9.81 x 0.6 + F x 1.5 =0
F = 43 x 0.6/1.5
F = 168.732 N (upward force)
Summation of forces in y direction is zero.
R -W +F= 0
Where, R is the normal force, W is the Weight force and F is the applied force.
Thus, this is the equation representing all the three forces acting on wheelbarrow.
Learn more about moment of force.
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Answer:
2697.75N/m
Explanation:
Step one
This problem bothers on energy stored in a spring.
Step two
Given data
Compression x= 2cm
To meter = 2/100= 0.02m
Mass m= 0.01kg
Height h= 5.5m
K=?
Let us assume g= 9.81m/s²
Step three
According to the principle of conservation of energy
We know that the the energy stored in a spring is
E= 1/2kx²
1/2kx²= mgh
Making k subject of formula we have
kx²= 2mgh
k= 2mgh/x²
k= (2*0.01*9.81*5.5)/0.02²
k= 1.0791/0.0004
k= 2697.75N/m
Hence the spring constant k is 2697.75N/m
3. An object will float if its density is less than the matter it is submerged in.
If it sinks in water, its density is more than 1. If it floats in glycerin, its density is less than 1.26.
Answer:
163 N
Explanation:
The density of copper is about 8.96. The ratio of the weight in water to the weight in air is about 1-1/ρ, so is about 0.8884.
0.8884 × 184 N ≈ 163 N
The submerged weight is about 163 N.
