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Yuliya22 [10]
3 years ago
7

Why is the level of glycerin initially decreases when heated ?​

Physics
1 answer:
Mila [183]3 years ago
4 0
Because glucerin is hotter so it decreases faster
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A physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Oiled Steel fry
Alinara [238K]

Answer:

N  = 6.67 N

Explanation:

The frictional or frictional force is a force that arises from the contact of two bodies and opposes movement.

The friction is due to imperfections and roughness, mainly microscopic, that exist on the surfaces of the bodies. Upon contact, these roughnesses engage with each other making movement difficult. To minimize the effect of friction, either the surfaces are polished or lubricated, since the oil fills the imperfections, preventing them from snagging.

As the frictional force depends on the materials and the force exerted on one another, its magnitude is obtained by the following expression:

f = μ*N    Formula (1)

where:  

f is the friction force  (N)

μ is the coefficient of friction

N is the normal force (N)

Data

f = 0.2 N : frictional force between the steel spatula and the Oiled Steel frying pan

μ = 0.03 :coefficient of kinetic friction between the two materials

Calculating of normal force

We replace data in the formula (1)

f = μ*N  

0.2  = 0.03*N  

N  = 0.2 / 0.03

N  = 6.67 N

5 0
3 years ago
If you need 40.0 Nm of torque in order to loosen a nut on a wn
KonstantinChe [14]

Answer:

0.301 m

Explanation:

Torque = Force × Radius

τ = Fr

40.0 Nm = 133 N × r

r = 0.301 m

The mechanic must apply the force 0.301 m from the nut.

6 0
3 years ago
A certain light truck can go around a flat curve having a radius of 150 m with a maximum spee dof 32.0 m/s. With what maximum sp
Dvinal [7]

Answer

Maximum speed at 75 m radius will be 22.625 m /sec

Explanation:              

We have given radius of the curve r = 150 m

Maximum speed v_{max}=32m/sec

Coefficient of friction \mu =\frac{v_{max}^2}{rg}=\frac{32^2}{150\times 9.8}=0.6965

Now new radius r = 75 m

So maximum speed at new radius v_{max}=\sqrt{\mu rg}=\sqrt{0.6965\times 75\times 9.8}=22.625m/sec

7 0
3 years ago
a particle with a charge of 5.5 x 10^-8 c is 3.5 cm from a particle with a charge of -2.3 x10^-8 c. the potential energy of this
Yuri [45]

Answer:

-32.5 * 10^-5 J

Explanation:

The potential energy of this system of charges is;

Ue = kq1q2/r

Where;

k is the Coulumb's constant

q1 and q2 are the magnitudes of the charges

r is the distance of separation between the charges

Substituting values;

Ue = 9.0×10^9 N⋅m2/C2 * 5.5 x 10^-8 C *( -2.3 x10^-8) C/(3.5 * 10^-2)

Ue= -32.5 * 10^-5 J

4 0
3 years ago
A reconnaissance plane flies 556 km away from
9966 [12]

We use the formula, to calculate the average speed of the round trip,

v_{av} =\frac{d_{total}}{t_{total}}

Here, d_{total}, is total distance covered by plane in total time, t_{total}.

For the round trip,

d_{total=556\ km+556\ km=1112 \times 10^3\ m

t_{total}=\frac{556 \times 10^3 m}{832 m/s} + \frac{556 \times 10^3 m}{1248 m/s}.

Thus,

v_{av} =\frac{1112 \times 10^3\ m}{\frac{556 \times 10^3 m}{832 m/s} + \frac{556 \times 10^3 m}{1248 m/s}} =\frac{1112 \times 10^3\ m}{668.26\ s+445.51\s} \\\\v_{av}=998.41\ m/s.


5 0
3 years ago
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