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trapecia [35]
2 years ago
13

Calculate the volume (liters) of solution that can be prepared from 180. grams of K2Cr2O7 for a 0.200M solution.

Chemistry
1 answer:
Sladkaya [172]2 years ago
8 0

Answer:

The volume of the solution is 0.305 liters.

Explanation:

Molar mass is the amount of mass that a substance contains in one mole. The molar mass of K₂Cr₂O₇ is 294 g / mole. Then you can apply the following rule of three: if by definition of molar mass 294 grams of the compound are contained in 1 mole, 180 grams are contained in how many moles?

moles=\frac{180 grams*1mole}{294 grams}

moles= 0.61

Molarity is a measure of the concentration of a substance that is defined as the number of moles contained in a certain volume. So, the molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

molarity=\frac{number of moles of solute}{volume}

Molarity is expressed in units \frac{moles}{liter}.

In this case:

  • molarity= 2 M
  • number of moles of solute= 0.61 moles
  • volume= ?

Replacing in the definition of molarity:

2 M=\frac{0.61 moles}{volume}

Solving:

volume=\frac{0.61 moles}{2 M}

volume= 0.305 liters

<u><em>The volume of the solution is 0.305 liters.</em></u>

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If 1.0g of rubidium and 1.0 g of bromine are reacted what will be left in measurable amounts in the reaction
pentagon [3]

Answer:

                     0.0639 g of Br₂ will be left

Explanation:

                    The balance chemical equation for given synthesis reaction is,

                                          2 Rb + Br₂ → 2 RbBr

Step 1: <u>Calculate Moles of each reactant for given masses as;</u>

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Moles of Rb = 0.0117 moles

Similarly,

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Moles of Br₂ = 0.00625 moles

Step 2: <u>Find reactant in Excess as:</u>

According to equation,

                    2 moles of Rb reacted with  =  1 mole of Br₂

So,

              0.0117 moles of Rb will react with  =  X moles of Br₂

Solving for X,

                      X  =  0.0117 mol × 1 mol / 2 mol

                     X =  0.00585 mol of Br₂

While, as calculated above we are provided with 0.00625 moles of Br₂. Therefore, Br₂ is in excess and the excess amount is calculated as,

= Given Moles - Consumed Moles

= 0.00625 moles - 0.00585 moles

= 0.0004 moles

Step 3: <u>Calculate mass of excess Br₂ as:</u>

Mass = Moles × M.Mass

Mass = 0.0004 mol × 159.80

Mass = 0.0639 g of Br₂

Note: Speaking broadly, there will be 1.93 g of RbBr along with 0.0639 g of Br₂ because RbBr is being produced and is available along with unreacted Br₂.

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Aluminum reacts with copper 2 chloride to make aluminum chloride and copper. Right the balanced equation
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Answer:

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saw5 [17]
Answer:
             There is more space between gas particles than the size of the particles.

Explanation:
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