The moles of MnO formed with the reaction of 5 moles of Mn is 3 moles.
<h3>What is a limiting reagent?</h3><h3 />
In a chemical reaction, the reagent that is present in a lesser quantity and governs the rate of the reaction is termed as the limiting reagent.
In the reaction of the formation of MnO, according to the stoichiometric law 2 moles of Mn reacts with 1 moles of Oxygen.
Thus, the moles of oxygen consumed by 7 moles of Mn is:
2 moles Mn = 1 mole O₂
7 moles Mn = 3.5 moles O₂
The available moles of O₂ = 5 mol.
The remaining moles of O₂ = 5-3.5 moles
The remaining moles of O₂ = 1.5 moles
The reaction of 5 moles Mn requires 2.5 moles of O₂, whereas the available moles of oxygen is 1.5 moles. Thus, oxygen serves as the limiting reagent.
The moles of MnO formed with the reaction of 5 moles Mn and 1.5 moles O₂
1 mole O₂ = 2 moles MnO
1.5 moles O₂ = 2 * 1.5 moles MnO
1.5 moles O₂ = 3 moles MnO
Thus, the moles of MnO formed with the reaction of 5 moles of Mn with the available oxygen is 3 moles.
Learn more about stoichiometric law, here:
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