List and describe the two major types of plastics.

Chemistry

1 answer:

stiv31 [10]3 years ago

7 0

Answer:

Thermoplastics and thermosets

Explanation:

The two key categories of plastic are thermoplastics and thermosetting plastics (thermosets). Thermoplastic products have the ability to be continually softened, melted and reshaped/recycled, for instance in injection molding or extrusion resins. However, thermoset products do not have this property.

You might be interested in

In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?

m_a_m_a [10]

Correct answer -->filtration

8 0

3 years ago

Given the formula: what is a chemical name of this compound? propane propanal propanol propanone

katrin [286]

1) Chemical formula for propane is CH₃-CH₂-CH₃.
Propane is a three carbon alkane (acyclic saturated hydrocarbon).
2) Chemical formula for propanal is CH₃-CH₂-CH=O.
Propanal is a saturated three carbon aldehyde (have a carbonyl center).
3) Chemical formula for propanol is CH₃-CH₂-CH₂-OH.
1-propanol is a primary alcohol.
4) Chemical formula for propanone is (CH₃)₂-C=O.
Propanone or acetone is he simplest and smallest ketone.

7 0

3 years ago

PLS HELP QUICK ALOTTT OF POINTS

timofeeve [1]

Answer:

$\boxed {\boxed {\sf 0.80 \ mol\ F}}$

Explanation:

We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.

We will convert using dimensional analysis and set up a ratio using Avogadro's Number.

$\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}$

We are converting 4.8 × 10²³ fluorine atoms to moles, so we multiply the ratio by this number.

$4.8 \times 10^{23} \ atoms \ F *\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}$

Flip the ratio so the units of atoms of fluorine cancel each other out.

$4.8 \times 10^{23} \ atoms \ F *\frac { 1 \ mol \ F}{6.022 \times 10^{23} \ atoms \ F}$

$4.8 \times 10^{23} *\frac { 1 \ mol \ F}{6.022 \times 10^{23} }$

Condense into 1 fraction.

$\frac { 4.8 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ F$

Divide.

$0.7970773829 \ mol \ F$

The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we found, that is the hundredths place. The 7 in the thousandths tells us to round the 9 in the hundredths place up to a 0. Then, we also have to round the 7 in the tenths place up to an 8.

$0.80 \ mol \ F$