Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
Answer:
2 x 2 x 2 x 2 x 2 x 5 x 13
Step-by-step explanation:
The Prime Factorization is:
2 x 2 x 2 x 2 x 2 x 5 x 13
In Exponential Form:
25 x 51 x 131
CSV Format:
2, 2, 2, 2, 2, 5, 13
Answer:
d it adds the two up and only mutiplys terris amount.
Answer:
(X-6) √x^2+2x-15 \ x^2 +2x - 15
$64x20%=$12.80
$64-$12.80=$51.20
