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3 years ago

Determine the bond type formed between Hg and F

Chemistry

1 answer:

charle [14.2K]3 years ago

6 0

Answer:

Multivalent Ionic

Explanation:

The type of bond formed between the atoms of two elements can easily be deduced from the magnitude of electronegativity difference between the two bonding atoms.

A summary of electronegativity differences and corresponding types of bonds are shown below as adapted from chemlibretexts, where Δχ is the difference in electronegativity ;

ionic if Δχ ≥ 2.0

polar if 2.0 > Δχ > 0.5

nonpolar if 0.5 > Δχ

To determine the type of bond between Hg and F. Hg has an electronegativity of 2 while F has an electronegativity of 4. the difference in electronegativity (Δχ) is 4 - 2 = 2

This corresponds to a multivalent ionic bond because mercurous ion is the

Hg2^2+ ion and this leads to the formation of Hg2X2 (mercury I fluoride).

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Buffer preparation. You wish to prepare a buffer consisting of acetic acid and sodium acetate with a total acetic acid plus acet

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Answer:

0.182 moles of acetic acid are needed, this means 10.93 g.

0.318 moles of sodium acetate are needed, this means 26.08 g.

Explanation:

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pH = pka + $log\frac{[A^{-} ]}{[HA]}$

In this case, [A⁻] is the concentration of sodium acetate, and [HA] is the concentration of acetic acid. The pka is a value that can be looked up in literature: 4.76.

From the problem we know that

[A⁻] + [HA] = 250 mM = 0.250 M eq. 1

We use the <em>H-H</em> equation, using the data we know, to describe [A⁻] in terms of [HA]:

5.0 = 4.76 + $log\frac{[A^{-} ]}{[HA]}$

$0.24=log\frac{[A^{-} ]}{[HA]}\\\\10^{0.24}=\frac{[A^{-} ]}{[HA]}\\ 1.74 [HA] = [A^{-}]$ eq.2

Now we replace the value of [A⁻] in eq. 1, to calculate [HA]:

1.74 [HA] + [HA] = 0.250 M

[HA] = 0.091 M

Then we calculate [A⁻]:

[A⁻] + 0.091 M = 0.250 M

[A⁻] = 0.159 M

Using the volume, we can calculate the moles of each substance:

moles of acetic acid = 0.091 M * 2 L = 0.182 moles
moles of sodium acetate = 0.159 M * 2 L = 0.318 moles

Using the molecular weight, we can calculate the grams of each substance:

grams of acetic acid = 0.182 mol * 60.05 g/mol = 10.93 g
grams of sodium acetate = 0.318 mol * 82.03 g/mol = 26.08 g

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