Answer:
Yes, your answers are correct.
The volume of a cone is given by V = 1/3πr²h. Since the diameter of the first cone is 4, the radius is 2; therefore the volume is
V = 1/3π(2²)(8) = 32π/3
We divide the volume of the sink, 2000π/3, by the volume of the cone:
2000π/3 ÷ 32π/3 = 2000π/3 × 3/32π = 6000π/96π = 62.5 ≈ 63.
The diameter of the second conical cup is 8, so the radius is 4. The volume then is:
V = 1/3π(4²)(8) = 128π/3
Dividing the volume of the sink, 2000π/3, by 128π/3:
2000π/3 ÷ 128π/3 = 2000π/3 × 3/128π = 6000π/384π = 15.625 ≈ 16
Answer:
-7/2y
Step-by-step explanation:
cancel out the Z's than youre left with -7/2y :}
3x(2) + 2(2x - 20) = 16 - 2x(2)
6x + 4x - 40 = 16 - 4x
10x - 40 = 16 - 4x
14x - 40 = 16
14x = 56
x = 4
Hope this helps! ;)
The given function is
The general form of the cosine function is
a is the amplitude
2pi/b is the period
c is the phase shift
d is the vertical shift
By comparing the two functions
a = 4
b = pi
c = 0
d = 1
Then its period is
The equation of the midline is
Since the maximum is at the greatest value of cos, which is 1, then
Since the minimum is at the smallest value of cos, which is -1, then
Then substitute them in the equation of the midline
The answers are:
Period = 2
Equation of the midline is y = 1
Maximum = 5
Minimum = -3
B-8 would be the answer. This is because we are saying you have 8 less than something. So no matter what something is, we are taking away 8 from it. Since our something is unknown, we use our variable 'b' in its place, and subtract 8, giving us b-8.<span />
