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3 years ago

Whats wavelength? pls explain in 8th grade form pls

Physics

1 answer:

xxTIMURxx [149]3 years ago

4 0

Answer:

Wavelength is the distance from one wave ray to the next. They can be from trough to trough or from crest to crest.

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the battery of a car has a rating stated which permit you to estimate the length of time a fully charged battery could deliever

Lubov Fominskaja [6]

Answer:

600Joules

Explanation:

The energy stored by this battery is calculated using the energy formula;

E = Q× v

Where E is energy

Q is the charge

v is voltage

Hence E = 50 × 12 = 600Joules

Note Q = 12 ampere minute

5 0

3 years ago

Please help me with this i dont know it

Inessa05 [86]

Answer:

no it would not. that is an open circuit and it would need to be closed at the switch for current to flow.

5 0

3 years ago

Can it is possible to complete half syllabus of physics class 11 in 8 days?

castortr0y [4]

Answer:

In the human thoughts, there is possible and impossible. In God's world everything is possible. If you keep thinking this you'll never start to study. Just get up, open the book and start to study like you do. Believe in yourself!

3 0

3 years ago

The kinetic energy of a rotating body is generally written as K=12Iω2, where I is the moment of inertia (also known as rotationa

agasfer [191]

Answer

given,

expression of Kinetic energy of rotating body

$K = \dfrac{1}{2}I\omega^2$

ω = 34.0 rad/s

Assuming mass of the particle equal to 13 Kg

and perpendicular distance from the particle to the axis is r = 1.25 m

now,

moment of inertia of particle = ?

from the given expression

$I= \dfrac{2K}{\omega^2}$ ..............(1)

we know

$K = \dfrac{1}{2}mv^2$

v = r ω

$K = \dfrac{1}{2}mr^2\omega^2$

putting value in equation (1)

$I= \dfrac{2\dfrac{1}{2}mr^2\omega^2}{\omega^2}$

$I =mr^2$

$I =13 \times 1.25^2$

I = 20.3125 kg.m²

4 0

3 years ago

A two-liter bottle is one-fourth full of water and three-quarters full of air. The air in the bottle has a gage pressure of 340

Fantom [35]

Answer:

The value is $P_G = 2.925 *10^{5} \ Pa$

Explanation:

From the question we are told that

The volume of the bottle is $v = 2 \ L = 2 * 10^{-3} \ m^3$

The gauge pressure of the air is $P_g = 340 \ kPa = 340 *10 ^{3} \ Pa$

Generally the volume of air before the bottle is turned upside down is

$V_a = \frac{3}{4} * V$

$V_a = \frac{3}{4} * 2 *10^{-3}$

$V_a = 0.0015 \ m^3 }$

Generally the volume air when the bottle is turned upside-down is

$V_u = \frac{5}{6} * 2 *10^{-3}$

$V_u = 0.00167 \ m^3$

From the the mathematical relation of adiabatic process we have that

$P_g * V_a^r = P_G * V_u^r$

Here r is a constant with a value r = 1.4

$340 *10 ^{3} * 0.0015^{1.4} = P_G * 0.00167^{1.4}$

$P_G = 2.925 *10^{5} \ Pa$

3 0

3 years ago