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jeyben [28]
3 years ago
9

An average force of 328 N acts for a time interval of 0.05s on a golf ball

Physics
1 answer:
blagie [28]3 years ago
4 0
Depends on how strong you are. People can hit it anywhere between a few inches and 500 yards.
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Help pls i need this right now
pantera1 [17]

Answer:

The x-component of F_{3} is 56.148 newtons.

Explanation:

From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:

\vec F_{1} + \vec F_{2} + \vec F_{3} = \vec O (1)

Where:

\vec F_{1}, \vec F_{2}, \vec F_{3} - External forces exerted on the ring, measured in newtons.

\vec O - Vector zero, measured in newtons.

If we know that \vec F_{1} = (70.711,70.711)\,[N], \vec F_{2} = (-126.859, 46.173)\,[N], F_{3} = (F_{3,x},F_{3,y}) and \vec O = (0,0)\,[N], then we construct the following system of linear equations:

\Sigma F_{x} = 70.711\,N - 126.859\,N +F_{3,x} = 0\,N (2)

\Sigma F_{y} = 70.711\,N + 46.173\,N+F_{3,y} = 0\,N (3)

The solution of this system is:

F_{3,x} = 56.148\,N, F_{3,y} = -116.884\,N

The x-component of F_{3} is 56.148 newtons.

5 0
2 years ago
If humans originated in Africa and migrated to other parts of the world some time would be required for this to occur.At the mod
Thepotemich [5.8K]

Answer:

100 years

Explanation:

10,000 divided by 100 equals 100

7 0
3 years ago
A particle (q = +5.0 µC) is released from rest when it is 2.0 m from a charged particle which is held at
PilotLPTM [1.2K]
The answer to your question is A. Have a great day
3 0
2 years ago
The player who tries to take the ball away from the offensive and give it to a midfielder to start an attack is called the _____
stiv31 [10]

Answer:

D. sweeper

Explanation:

i did the assignment and got it right

4 0
2 years ago
A race car's velocity increases from +28 m/s to +36 m/s over a 2.0-s time interval. What is the car's
BigorU [14]

Answer:

4 m/s^{2}

Explanation:

Acceleration, a=\frac {v-u}{t}

Where v and u are the final and initial velocities of the race car respectively, t is the time taken for the race car to attain velocity of 36 m/s.

Substituting 36 m/s for v, 28 m/s for u and 2 s for t then

a=\frac {36 m/s-28 m/s}{2}=4 m/s^{2}

3 0
3 years ago
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