F=m*a and m is constant on any planet
25000-m*g=m*1.2
10000-m*g=-m*0.80
m*g is the weight
25000/1.2-m*g/1.2=m
10000/0.80-m*g/0.80=-25000/1.2+m*g/1.2 solve for m*g
m*g=(10000/0.80+25000/1.2)/ (1/1.2+1/0.80)
16 kN
Answer:
BA
0

Explanation:
B = Magnetic field
A = Area
= Angle
t = Time taken
Before rotation the magnetic flux is given by

Magnetic flux is BA
After rotation the magnetic flux is given by

The magnetic flux is 0
Magnitude of emf is given by

The magnitude of the average emf induced in the entire coil is 
Answer:
![[F]=[MLT^{-2}]](https://tex.z-dn.net/?f=%5BF%5D%3D%5BMLT%5E%7B-2%7D%5D)
Explanation:
Newton’s second law states that the acceleration a of an object is proportional to the force F acting on it is inversely proportional to its mass m. The mathematical expression for the second law of motion is given by :
F = m × a
F is the applied force
m is the mass of the object
a is the acceleration due to gravity
We need to find the dimensions of force. The dimension of force m and a are as follows :
![[m]=[M]](https://tex.z-dn.net/?f=%5Bm%5D%3D%5BM%5D)
![[a]=[LT^{-2}]](https://tex.z-dn.net/?f=%5Ba%5D%3D%5BLT%5E%7B-2%7D%5D)
So, the dimension of force F is,
. Hence, this is the required solution.
For this problem, we use the derived equations for rectilinear motion at constant acceleration. The equations used for this problem are:
a = (v - v₀)/t
2ax = v² - v₀²
where
a is the acceleration
x is the distance
v is the final velocity
v₀ is the initial velocity
t is the time
The solution is as follows;
a = (60mph - 30 mph)/(3 s * 1 h/3600 s)
a = 36,000 mph²
2(36,000 mph²)(x) = 60² - 30²
Solving for x,
x = 0.0375 miles
Answer:
The work done is "2000 J".
Explanation:
The given values are:
Force,
F = 200 N
Mass,
m = 55 kg
Displacement,
d = 10 m
Now,
The work done will be:
⇒ 
On substituting the given values, we get
⇒ 
⇒ 