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Inessa05 [86]
3 years ago
10

4.01 ESSENTIAL QUESTIONS

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0

Answer:

You use distance and slope formula to classify a quadrilateral by using the x and y coordinates of the quadrilateral. Boom

Step-by-step explanation:

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Multiplying a number by 3 is equal to sum of the number and 5.
DerKrebs [107]

Answer:

this makes no sense

Step-by-step explanation:

6 0
2 years ago
What’s 6 times 251 in expanded form? HELP!!
kramer

Answer:

1506

Step-by-step explanation:

1,506 = (1 x 1000) + (1 x 00) + (0 x 0) + (6 x 1)

8 0
3 years ago
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Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
Please help will mark brainliest
Levart [38]

Answer:

14

Step-by-step explanation:

7 0
3 years ago
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Solve this polynomial:
nadezda [96]

Answer:

  4ab +10b

Step-by-step explanation:

Perhaps you want to simplify the expression.

  (2.5ab+14b)-(-1.5ab+4b)=2.5ab+14b+1.5ab-4b\\\\=ab(2.5+1.5)+b(14-4)=\boxed{4ab+10b}

8 0
3 years ago
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