Answer:
(27.3692 ; 44.6308)
Step-by-step explanation:
Mean, xbar = 36
Standard deviation, s = 11
Sample size, n = 12
Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718
Confidence interval :
Xbar ± Margin of error
Margin of Error = Tcritical * s/sqrt(n)
Margin of Error = 2.718 * 11/sqrt(12) = 8.6308
Confidence interval :
Lower boundary : 36 - 8.6308 = 27.3692
Upper boundary : 36 + 8.6308 = 44.6308
(27.3692 ; 44.6308)
Answer:
2/36
Step-by-step explanation:
The only outcomes that lead to a sum of 3 are (2,1) and (1,2) therefore there is only a 2 in 36 chance of rolling a sum of 3
Answer:
X 2 -7
-9 -18 126
3 -54 -6,804
1944 7.71
0.00396604938
Step-by-step explanation:
I tried. Sorry if it's wrong I've never done a mathematical punnet square before.
Answer:(
q
p+1)
2
+4
Step-by-step explanation:
Answer:
the length of the conjugate axis is 16
Step-by-step explanation:
We know that the general equation of a hyperbola with transverse horizontal axis has the form:
Where the point (h, k) are the coordinates of the center of the ellipse
2a is the length of the transverse horizontal axis
2b is the length of the conjugate axis
In this case the equation of the ellipse is:
Then
Finally the length of the conjugate axis is 16
