Answer:
4
Step-by-step explanation:
Here you need not completely solve 7992 squared. You can just take the last digit which in this case is 2 and solve for the square of that digit. 2 x 2 = 4. Now if it was a bigger digit which would result in a two digit number when squared you would take the last digit of that number. But, we don't need to do that here since 2 squared is 4.
It’s A it’s honestly a simple equation just can’t explain it in typing
1 1/2 * 3/4 =
Change 1 1/2 to an improper fraction = 3/2
3/2 * 3/4 = 6/4 * 3/4
6/4 * 3/4 = 18/4 = 4 2/4 = 4 1/2
The answer is 4 1/2.
Hope this helped☺☺
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5