Complete question
The complete question is shown on the first uploaded image
Answer:
The value is
Explanation:
From the question we are told that
The equation is

Generally the equilibrium is mathematically represented as
Here
is the concentration of water vapor which is mathematically represented as
![[H_2O ] = \frac{n_w}{V_s }](https://tex.z-dn.net/?f=%5BH_2O%20%5D%20%3D%20%20%5Cfrac%7Bn_w%7D%7BV_s%20%7D)
Here
is the volume of the solution given as 8.9 L
is the number of moles of water vapor which is mathematically represented as

Here
is the mass of water given as 2.00 g
and
is the molar mass of water with value 18 g/mol
So

=> 
So
![[H_2O ] = \frac{0.11}{8.9 }](https://tex.z-dn.net/?f=%5BH_2O%20%5D%20%3D%20%20%5Cfrac%7B0.11%7D%7B8.9%20%7D)
=> ![[H_2O ] = 0.01236 \ M](https://tex.z-dn.net/?f=%5BH_2O%20%5D%20%3D%200.01236%20%5C%20%20M%20)
Also
is the concentration of hydrogen gas which is mathematically represented as
![[H ] = \frac{n_v}{V_s }](https://tex.z-dn.net/?f=%5BH%20%5D%20%3D%20%20%5Cfrac%7Bn_v%7D%7BV_s%20%7D)
Here
is the volume of the solution given as 8.9 L
is the number of moles of hydrogen gas which is mathematically represented as

Here
is the mass of water given as 4.77 g
and
is the molar mass of water with value 2 g/mol
So

=> 
So
![[H_2O ] = \frac{2.385}{8.9 }](https://tex.z-dn.net/?f=%5BH_2O%20%5D%20%3D%20%20%5Cfrac%7B2.385%7D%7B8.9%20%7D)
=> ![[H_2O ] = 0.265 \ M](https://tex.z-dn.net/?f=%5BH_2O%20%5D%20%3D%20%200.265%20%5C%20%20M%20)
So
=>
Answer:
Exactly the same approach can be used for determination of bromides. Other halides and pseudo halides, like I- and SCN-, behave very similarly in the solution, but their precipitate tends to adsorb chromate anions making end point detection difficult.
Hope it helps!
Answer:
It favors the forward reaction.
Explanation:
According to Le Chatelier's Principle, when a system at equilibrium suffers a perturbation, the system will react in order to counteract the effect of such perturbation.
If more reactant is added, the system will try to decrease its concentration. It will do so by favoring the forward reaction, decreasing the concentration of the reactant and increasing the concentration of the products, in order to re-establish the equilibrium.
Answer:
D
Explanation:
Breaking bonds absorbs (Requires) energy. Forming bonds releases it. It's kinda backwards but that's how it works. :)