Answer:
substrate-level phosphorylation 
Explanation:
Substrate-level phosphorylation is the metabolic reaction which results in formation of energy currency molecules, ATP or GTP by direct transfer of a phosphoryl group to the ADP or GDP from the another phosphorylated compound.
<u>In citric acid cycle, Succinyl-CoA in the presence of succinyl-CoA synthase is converted to succinate. Condensation reaction (Substrate-level phosphorylation) of GDP and Pi takes place which results in the formation of GTP.</u>
 
        
             
        
        
        
What I’m seeing on quizlet says what you’re describing is a ball-and-stick model.
        
                    
             
        
        
        
Answer:
 Lipase is an enzyme the body uses to break down fats in food so they can be absorbed in the intestines.
Explanation:
i hope this will help you :)
 
        
             
        
        
        
The δs∘rxn  for the reaction  →
 →  will be -146 J/K.
 will be -146 J/K.
Entropy would be a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty.
Entropy would be a measurement of the system's unpredictability or disorder. The entropy increases as randomness do. It has broad properties as well as a state function. It has the unit  .
.
Entropy of the reaction can be calculated by the reaction.
Δ = 2 mol ×
 = 2 mol ×  ×
 ×  - 1 mol ×
 - 1 mol × 
Δ = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol  ×205.2 J/mol.K
  = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol  ×205.2 J/mol.K
Δ = -146.8 J/K
  = -146.8 J/K
Therefore, the δs∘rxn  for the reaction  →
 →  will be -146 J/K.
 will be -146 J/K.
To know more about reaction
brainly.com/question/20305735
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MThe  heat  energy  required  to  raise  the  temperature   of  0.36Kg   of  copper   from   22 c   to  60  c  is  calculate  using  the  following  formula
MC delta T
m(mass)=  0.360kg  in  grams  =  0.360  x1000 = 360 g
  c(specific  heat  energy)  =  0.0920  cal/g.c
delta T =  60- 23  = 37  c
heat  energy is therefore=  360g   x0.0920 cal/g.c  x 37  c=  1225.44  cal