Those reactions in which Alkyl Halide reacts with the solvent without the involvement of any acid or base is called as
Solvolysis. In given problem <em>tert</em>-Butyl Bromide is a tertiary Alkyl Halide and we know well that tertiary alkyl halides undergo
SN¹ and
E¹ elimination reaction due to the formation of
stable tertiary carbocation. In given example after the formation of carbocation when Isopropyl act as
nucleophile it will produce
ether and when it acts as a
base it will produce
unsaturated compound. The reaction along with both products is shown below,
Answer:
304.19 g
Explanation:
M(H2) = 2*1 = 2 g/mol
54.1 g H2 * 1 mol H2/2gH2 = 27.05 mol H2
3H2 + N2 ------> 2NH3
from reaction 3 mol 2 mol
given 27.05 mol x mol
x = 27.05*2/3 = 18.03 mol NH3
M(NH3) = 14 +3*1 = 17 g/mol
18.03 mol NH3 * 17 g NH3/ 1 mol NH3 ≈ 307 g
Closeet answer is 304.19 g.
the awnser is 87 hope this helped
The energy needed to remove an electron from an atom is called ionization energy.