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3 years ago

9

Please please help me please it’s due today at 5:10pm please help it’s an test I really need help please please help me please p

lease thank you

1 answer:

egoroff_w [7]3 years ago

6 0

Answer:

D

Step-by-step explanation:

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Write the correct verb

Dafna1 [17]

Answer:

Will

Step-by-step explanation:

The key word in this sentence is tomorrow, because tomorrow is in the future, therefore your answer is will.

6 0

3 years ago

You have been hired as a marketing consultant to Johannesburg Burger Supply, Inc., and you wish to come up with a unit price for

BartSMP [9]

Answer:

The demabd function is:

$q(p)= -4500p+18000$

Step-by-step explanation:

The demand follow the linear equation $q(p)=mp+b$

1. When p=$2.00 and q=9000, the equation is:

$9000=m(2.00)+b (1)$

2. Whe p=$4.00 and q=0, the equation is:

$0=m(4.00)+b (2)$

3. Solve equation (1) for b:

$9000=2m+b\\9000-2m=2m+2m+b\\9000-2m=b$

4. Replace the value of b in equation (2)

$0=4m+b\\0=4m+9000-2m\\0=2m+9000\\0-9000=2m+9000-9000\\-9000=2m\\\frac{-9000}{2m}=\frac{2m}{2m}\\ -4500=m$

The value of m is 4500

5. Calculate b, replacing m:

$0=4m+b\\\\0=4(-4500)+b\\0=-18000+b\\18000=b$

The value of b is 18000

3 0

3 years ago

Using Unit Rates to compare Ratios continued

nasty-shy [4]

Answer:

Brandon

Step-by-step explanation:

GIVEN: Branden and Pete each play running back. Branden carries the ball $75$ times for $550$ yards, and Pete has $42$ carries for $380$ yards.

TO FIND: Who runs farther per carry.

SOLUTION:

Total yards traveled by Brandon $=550\text{yards}$

No. of times ball carried by Brandon $=75\text{ times}$

Average yards per carry for Brandon $=\frac{\text{total yards traveled}}{\text{number of times ball carried}}$

$=\frac{550}{75}$

$=\frac{22}{3}\text{ yards per carry}$

$=7.33\text{ yards per carry}$

Total yards traveled by Pete $=380\text{ yards}$

No. of times ball carried by Pete $=42\text{ times}$

Average yards per carry for Pete $=\frac{\text{total yards traveled}}{\text{number of times ball carried}}$

$=\frac{380}{42}$

≅ $9\text{ yards per carry}$

As the number of yards per carry is higher for Brandon , therefore he runs farther per carry.

4 0

3 years ago

I need help on this.. And I will give you a BRANILIST if you the first one with the right answer

AlekseyPX

Answer:

0.1

Step-by-step explanation:

(9,4) (5,1) $\frac{y_{2} y_{1} }{x_{2} x_{1} }$ , plug in the numbers, $\frac{(1)(4)}{(5)(9)}$ = $\frac{4}{40} or \frac{1}{10}$ , to write it as a decimal, you divide the numerator by the denominator, 0.1

5 0

3 years ago

In a group of 90 seventh

Firdavs [7]

90 x .80= 72. 72 Students like hot choco, therefore 8 do no like hot choco

5 0

3 years ago

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