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AnnyKZ [126]
2 years ago
11

PLS HELP NO LINKS PLS What is the pH of normal rainfall?

Chemistry
2 answers:
rodikova [14]2 years ago
8 0

Answer:

between 5 and 5.5

Explanation:

pishuonlain [190]2 years ago
4 0

Answer:

between 5.0 and 5.5

Explanation:

between 5.0 and 5.5

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Redox titrations are used to determine the amounts of oxidizing and reducing agents in solution. For example, a solution of hydr
xxTIMURxx [149]

Answer:

0.374 g

Explanation:

Hello,

Since both the molarity and the volume allows us to know the moles of potassium permanganate, and we already have the balanced chemical reaction, the stoichiometric procedure that is attached in the picture, is developed to substantiate the the titrated mass of hydrogen peroxide was 0.374 g.

Best regards.

6 0
3 years ago
K2so4 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.450 m k2so4 solution.
amid [387]

<em>Answer:</em>

  • Conc. of K+ ions = 0.90 M
  • Coc. of SO4∧-2 = 0.45 M

<em>Explanation:</em>

<em>Data Given:</em>

Conc. of H2SO4 = 0.450

As sulphoric acid is a strong electrolyte, it completely dissociate into ions.

H2SO4 ⇆   2K+   +   SO4∧-2

.450 M K2SO4 means that there is .450 mols of K2SO4 in every liter of solution.

                      K2SO4  :  K+                                          K2SO4  : SO4∧-2

                          1      =     2                                                   1     =    1

                     0.450   =   2× 0.450 = 0.90                     0.450 =  0.450×1 = 0.450

<em> Result:</em>

Conc. of potassium ion will be 0.90M    

Coc. of sulphate ions will be 0.45 M

8 0
3 years ago
Balance this chemical equation. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici
larisa86 [58]
The first one have a nice day and good luck
8 0
3 years ago
What type of charge does each part of an atom have (positive, negative, no charge)
Masteriza [31]
Answer:
P-positive
N-negative
E-no charge
6 0
3 years ago
Read 2 more answers
A student is instructed to make 1 L of a 2.0 M solution of CaCl2 using dry salt. How should he do this?
Pachacha [2.7K]
<span>The student should follow following steps to make 1 L of </span>2.0 M CaCl₂.<span>
<span>
1. First he should calculate the number of moles of 2.0 M CaCl</span></span>₂ in 1 L solution.<span>

</span>Molarity of the solution = 2.0 M<span>
Volume of solution which should be prepared = 1 L

Molarity = number of moles / volume of the solution

Hence, number of moles in 1 L = 2 mol

2. Find out the mass of dry CaCl</span>₂ in 2 moles.<span>

moles = mass / molar mass

Moles of CaCl₂ = 2 mol</span><span>
Molar mass of CaCl₂ = </span><span>110.98 g/mol

Hence, mass of CaCl</span>₂ = 2 mol x <span>110.98 g/mol
                                     = 221.96 g

3. Weigh the mass accurately 

4. Then take a cleaned and dry1 L volumetric flask and place a funnel top of it. Then carefully add the salt into the volumetric flask and finally wash the funnel and watch glass with de-ionized water. That water also should be added into the volumetric flask.

5. Then add some de-ionized water into the volumetric flask and swirl well until all salt are dissolved.

<span>6. Then top up to mark of the volumetric flask carefully. 
</span>
</span>
7. As the final step prepared solution should be labelled.
4 0
3 years ago
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