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2 years ago

11

PLS HELP NO LINKS PLS What is the pH of normal rainfall?

2 answers:

rodikova [14]2 years ago

8 0

Answer:

between 5 and 5.5

Explanation:

pishuonlain [190]2 years ago

4 0

Answer:

between 5.0 and 5.5

Explanation:

between 5.0 and 5.5

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Jupiters atmosphere is mostly made of ___

erastovalidia [21]

Jupiter's atmosphere is composed predominantly of hydrogen and helium, but if you have to select any one option then we can look at the percentage of existence of these elements that would be
<span>90 percent hydrogen.
remaining 10 percent is helium
so choose Hydrogen.</span>

3 0

3 years ago

Vikki [24]

2nd

Explanation:

because i guesses i guess so yeah trust your gut buddy

5 0

2 years ago

Given the following heats of combustion. CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(l) ΔH°rxn = -726.4 kJ C(graphite) + O2(g) CO2(g) ΔH

sergeinik [125]

Answer:

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

Explanation:

The formation reaction of CH_3OH will be,

$C(s)+2H_2(g)+\frac{1}{2}O_2\rightarrow CH_3OH(g),\Delta H_{formation}=?$

The intermediate balanced chemical reaction will be,

$C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole$ ..[1]

$H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l), \Delta H_2=-285.8kJ/mole$ ..[2]

$CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole$ ..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2 then adding all the equations, Using Hess's law:

We get :

$C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole$ ..[1]

$2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol$ ..[2]

$CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole$ [3]

The expression for enthalpy of formation of $C_2H_4$ will be,

$\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3$

$\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)$

$\Delta H=-238.7kJ/mole$

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

4 0

2 years ago

What is the volume if 1.5 mol of gas has a pressure of 700 torr at 15°C?

Tasya [4]

Answer:

V = 38.48 L

Explanation:

Given that,

No. of moles = 1.5 mol

Pressure, P = 700 torr

Temperature, T = 15°C = 288 K

We need to find the volume of the gas. The ideal gas equation is given by :

$PV=nRT\\\\V=\dfrac{nRT}{P}\\\\V=\dfrac{1.5\times 62.36\times 288}{700}\\\\V=38.48\ L$ , R = L.Torr.K⁻¹.mol⁻¹

So, the required volume is equal to 38.48 L.

7 0

2 years ago

The Law of Superposition states

lora16 [44]

In an undisturbed sequence of layers of rocks, the younger layers lie on top of the older layers

8 0

2 years ago