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3 years ago

Look at the reaction below.

Chemistry

2 answers:

blondinia [14]3 years ago

6 0

Answer: $H_2SO_4(aq)$

Explanation:

An acid is defined as the acid which completely dissociates when dissolved in water and release $H^+$ ions in their aqueous states.

A base is defined as the base which completely dissociates when dissolved in water and releases $OH^-$ ions in their aqueous states.

$Mg$ is an element, $H_2$ is a compound, $MgSO_4$ is a salt formed by combination of acid and base.

The equation for the dissociation of sulphuric acid is given by:

$H_2SO_4(aq.)\rightarrow 2H^+(aq.)+SO_4^{2-}(aq.)$

Brut [27]3 years ago

4 0

Answer:

H2SO4

Explanation:

H2SO4 is actually one of the strongest acids, coming to a pH value very close to 1. Acids transfer their hydrogen ions to other substances, such as water, and usually have hydrogen in their formula. In this case, H2SO4 has hydrogen in its formula and is the acid in this case.

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How do the biosphere and geosphere interact? give an example

egoroff_w [7]

Answer:

Plants

Explanation:

Plants, part of the biosphere, grow in the soil, which is part of the geosphere

hope this helped :)

5 0

3 years ago

Chlorine and bromine are elements in Group VII.

Goryan [66]

Explanation:

Bromine is a chemical element with the symbol Br and atomic number 35. It is the third-lightest halogen, and is a fuming red-brown liquid at room temperature that evaporates readily to form a similarly coloured vapour. Its properties are intermediate between those of chlorine and iodine. Isolated independently by two chemists, Carl Jacob Löwig (in 1825) and Antoine Jérôme Balard (in 1826), its name was derived from the Ancient Greek βρῶμος ("stench"), referring to its sharp and disagreeable smell.

Bromine, 35Br

7 0

3 years ago

Can the nature of a reactant be altered to speed up reaction

Step2247 [10]

Answer:

yeet

Explanation:

yeet

6 0

3 years ago

calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of w

kipiarov [429]

Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is $-22Jmole^-^1k^-^1$

(b) The normal boiling point of water (J·K−1·mol−1) is $-109Jmole^-^1K^-^1$

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is 109J/mole

Explanation:

Lets calculate

(a) - General equation -

$(\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p$ = $-5_m(\beta )+5_m(\alpha )$ = $-\frac{\Delta H}{T}$

$\alpha ,\beta$ → phases

ΔH → enthalpy of transition

T → temperature transition

$(\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p$ = $= -\frac{\Delta_fH}{T_f}$

= $\frac{-6.008kJ/mole}{273.15K}$ ( $\Delta_fH$ is the enthalpy of fusion of water)

= $-22Jmole^-^1k^-^1$

(b) $(\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}$

= $\frac{40.656kJ/mole}{373.15K}$ ( $\Delta_v_a_p_o_u_rH$ is the enthalpy of vaporization)

= $-109Jmole^-^1K^-^1$

$[\mu(l-5$ ° $C)-\mu(l,0$ ° $C)]$ = $[\mu(s-5$ ° $C)-\mu(s,0$ ° $C)]$ $=-S_m$ ΔT

$\mu(l,-5$ ° $C)-\mu(s,-5$ ° $C)=-Sm\DeltaT [\mu(l,0$

$\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)$

= 109J/mole

6 0

2 years ago

How does increasing temperature increase the number of reactions?

antiseptic1488 [7]

Answer:

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction

Explanation:

7 0

3 years ago