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Galina-37 [17]
3 years ago
10

The diagram below shows an electromagnet. Using your scientific knowledge, state the device that is used to measure the potentia

l difference across the battery.

Chemistry
1 answer:
weeeeeb [17]3 years ago
8 0

Voltmeter is the device that is used to measure the potential difference across the battery.

<h2>What are the usage of voltmeter?</h2><h3 /><h3>Usage of Voltmeter</h3>

Voltmeter is an instrument that measures voltages of both direct and alternating electric current. On a scale of voltmeter usually graduated in volts, millivolts (0.001 volt), or kilovolts (1,000 volts).

Voltmeter is connected in parallel form. It has a high resistance so that it takes negligible current from the circuit so we can conclude that Voltmeter is the device that is used to measure the potential difference across the battery.

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What is the bonding continuum?
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Bonding Continuum<span>. Trends in the Periodic Table and </span>Bonding<span>. Ionic </span>Bonds. Ionic bonds<span> are formed between atoms with a large difference in electronegativities. ... The ionic </span>bond<span> is the electrostatic force of attraction between a positive and negative ion.</span>
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3 years ago
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Why do different solvents affect adsorbate-surface interactions?
Effectus [21]

Answer:

so that the can fiuger out what it is for the answer

Explanation:

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3 years ago
Platinum crystallizes with the face-centered cubic unit cell. The radius of a platinum atom is 139 pm. Calculate the edge length
horrorfan [7]

Answer:

Length = 393pm, Density = 21.3 g/cm^3.

Explanation:

From the question above, we have the following parameters or data which is going to aid in solving the above Question.

=> The radius of a platinum atom = 139 pm.

Therefore, the length can be calculated by making use of the formula given below:

Length = 2 √( 2r) = 2 × √ (2 × 139 × 10^-12m ) = 393 × 10^-10 m = 393pm.

The density can be calculated by making use of the chemical formula given below:

Density = mass ÷ volume = (195.064/ 6.02 × 10^23) ÷ (3.93 × 10^-10/ 10^-2) = 21.3 g/cm^3.

3 0
3 years ago
Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.57×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.46×10−19, what is the equilib
Dvinal [7]

<u>Answer:</u> The value of K_c for the final reaction is 7.16\times 10^{25}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  H_2S(aq.)\rightleftharpoons HS^-(aq.)+H^(aq.);K_1

<u>Equation 2:</u>  HS^-(aq.)\rightleftharpoons S^{2-}(aq.)+H^(aq.);K_2

The net equation follows:

S^{2-}(aq.)+2H^+(aq.)\rightleftharpoons H_2S(aq.);K_c

As, the net reaction is the result of the addition of reverse of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of inverse of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=\frac{1}{K_1}\times \frac{1}{K_2}

We are given:

K_1=9.57\times 10^{-8}

K_2=1.46\times 10^{-19}

Putting values in above equation, we get:

K_c=\frac{1}{(9.57\times 10^{-8})}\times \frac{1}{(1.46\times 10^{-19})}=7.16\times 10^{25}

Hence, the value of K_c for the final reaction is 7.16\times 10^{25}

5 0
3 years ago
Write the equation for the formation of a fluoride anion from a fluorine atom. If the electron affinity of the fluorine atom is
Finger [1]

Answer:

Part A. F + e⁻ → F⁻

Part B. -820 kJ

Part C. -5.45x10⁻²² kJ

Explanation:

Part A

The fluoride anion is formed when fluorine accepts an electron:

F + e⁻ → F⁻

Part B

The electron affinity is the energy necessary for the atom to accept 1 electron, which is exothermic, so it's negative. The total energy q is the electron affinity multiplied by the number of moles:

q = -328 kJ/mol * 2.5 mol

q = -820 kJ

Part C

By the Avogadros' number

1 mol --------- 6.02x10²³ atoms

x --------- 1 atom

By a simple direct three rule:

x = 1.66x10⁻²⁴ mol

So, the energy for 1 atom is:

q = -328 kJ/mol * 1.66x10⁻²⁴ mol

q = -5.45x10⁻²² kJ

5 0
3 years ago
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