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Galina-37 [17]
3 years ago
10

The diagram below shows an electromagnet. Using your scientific knowledge, state the device that is used to measure the potentia

l difference across the battery.

Chemistry
1 answer:
weeeeeb [17]3 years ago
8 0

Voltmeter is the device that is used to measure the potential difference across the battery.

<h2>What are the usage of voltmeter?</h2><h3 /><h3>Usage of Voltmeter</h3>

Voltmeter is an instrument that measures voltages of both direct and alternating electric current. On a scale of voltmeter usually graduated in volts, millivolts (0.001 volt), or kilovolts (1,000 volts).

Voltmeter is connected in parallel form. It has a high resistance so that it takes negligible current from the circuit so we can conclude that Voltmeter is the device that is used to measure the potential difference across the battery.

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The strongest of the intermolecular forces are hydrogen bonds
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Is it better for an element to be more abundant or less abundant?
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I believe it's better for it to be more abundant because it's better to have more then less. Take water as an example. Water is an important factor to our survival and if we didn't have enough of that we would be in trouble.  Or if we needed food but there wasn't enough more people would be dying from starvation. It's better to have a little more than a little less.

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3 years ago
7. Define electronegativity
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Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons.
5 0
3 years ago
There are 4.78 g of dry LICIO4 and
astraxan [27]

Answer:

The number of moles of H₂O is 0.135 mol.

The number of moles of LiClO₄ is 0.0449 mol.

Explanation:

Mole is an important standard unit used for the measurement of large quantities of atoms, molecules, or other particles. One mole is equal to 6.022×10²³ units.

The number of moles of a substance is calculated by:

\frac{mass of substance}{molecular weight of  substance}

To find the number of moles of H₂O:

Mass of H₂O in the sample = 2.43g

The molecular weight of H₂O = 18.02g

Number of moles = \frac{2.43}{18.02} = 0.135 mol.

To find the number of moles of LiClO₄:

Mass of LiClO₄ given = 4.78g

The molecular weight of LiClO₄ = 106.39g

Number of moles = \frac{4.78}{106.39} = 0.0449 mol.

Learn more about Moles here:

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4 0
2 years ago
A 17.11 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 21.71 g CO2 and 5.
Andru [333]

Answer:  The empirical formula and the molecular formula of the organic compound is CHO and C_4H_4O_4 respectively.

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2 = 21.71 g

Mass of H_2O= 5.926 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 21.71 g of carbon dioxide, =\frac{12}{44}\times 21.71=5.921g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 5.926 g of water, =\frac{2}{18}\times 5.926=0.658g of hydrogen will be contained.

Mass of oxygen in the compound = (17.11) - (5.921+0.658) = 10.53  g

Mass of C = 5.921 g

Mass of H = 0.658 g

Mass of O = 10.53 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.921g}{12g/mole}=0.493moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.658g}{1g/mole}=0.658moles

Mass of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{10.53g}{16g/mole}=0.658moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.493}{0.493}=1

For H =\frac{0.658}{0.493}=1

For O=\frac{0.658}{0.493}=1

The ratio of C : H: O =  1: 1: 1

Hence the empirical formula is CHO.

empirical mass of CHO = 12(1) + 1(1) + 1 (16) = 29

Molecular mass = 104.1 g/mol

n=\frac{\text {Molecular mass}}{\text {Equivalent mass}}=\frac{104.1}{29}=4

Thus molecular formula = n\times {\text {Empirical formula}}=4\times CHO=C_4H_4O_4

6 0
3 years ago
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