To
determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample
of the compound with the given composition. Then, we calculate for the number
of moles of each element. We do as follows:<span>
mass moles
C 56.79 4.73
H 6.56 6.50
O 28.37 1.77
N 8.28 0.59
Dividing the number of moles of each element with
the smallest value, we will have the empirical formula:
</span> moles ratio
C 4.73 / 0.59 8
H 6.50 / 0.59 11
O 1.77 / 0.59 3
N 0.59 / 0.59 1<span>
</span><span>
The empirical formula would be C8H11O3N.</span>
Answer:
Generally, observed behavior that can be formulated into a statement, sometimes mathematical in nature, is called a natural law- D.
14 since K has 1 valence but there’s two so 2 valence for k and oxygen has 6 but there’s two so 12
Answer:
2.78 moles of water are produced.
Explanation:
Given data:
Number of moles of H₂O produced = ?
Number of moles of oxygen react = 3.25 mol
Solution:
Chemical equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Now we will compare the moles of water with oxygen.
O₂ : H₂O
7 : 6
3.25 : 6/7×3.25 = 2.78 mol
