πAnswer:
Therefore, the area of a sector of a circle would be 13.5π square units.
Step-by-step explanation:
Given
mi
The area of a sector of a circle is:
A = π r² Ф/360
A = π (9)² 60/360
A = π 81 * 1/6
A = 13.5π square units
Therefore, the area of a sector of a circle would be 13.5π square units.
hello :
<span>help :
<span>the discriminat of each quadratic equation :
ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 ) Δ > 0 the equation has two reals solutions : x =
(-b±√Δ)/2a</span>
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions</span>
Answer:
3/4 or .75
Step-by-step explanation:
slope = dy/dx
dy = 1 - -2 = 3
dx = 2 - -2 = 4
slope = 3/4