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3 years ago

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A surface grinding operation is used to finish a flat plate that is 5.50 in wide and 12.500 in long. The starting thickness is 1

.085 in. After grinding the surface, the thickness is 1.000 in. The grinding wheel had a starting diameter of 6.013 in and a width of 0.50 in. After the operation, the diameter of the grinding wheel is 5.997 in. Determine the grinding ratio in this operation.

1 answer:

valina [46]3 years ago

5 0

Answer:

77.40

Explanation:

Initial width = 5.5 Inches

Initial length = 12.5 inches

Initial thickness = 1.085 inches

After grinding

Thickness of flat plate = 1 inch

Grinding wheel

starting diameter( di )= 6.013 inches

width of grinding wheel = 0.5 inch

After operation

Diameter of grinding wheel ( df ) = 5.997

<u>Calculate the grinding ratio in this operation</u>

First step : determine the volume of material removed from flat plate

= Length of flat plate * width of flat plate * change in thickness

= 12.5 * 5.5 * ( 1.085 - 1 )

= 5.8437 in^3

Volume of material from grinding wheel

= π / 4 * ( di^2 - df^2 ) * width

= π / 4 * ( 6.013^2 - 5.997^2 ) * 0.5

= 0.0755 in^3

<u>Finally the Grinding ratio</u>

= 5.8437 / 0.0755

= 77.4

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Answer:

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Explanation:

For this case we know the following info :

$V_i = 0.3 m^3$ represent the initial volume

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And we need to calculate the work associated to this process.

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If we replace the expression for P we got:

$W = \int_{V_i}^{V_f} a V^{-2} dV$

If we integrate we got:

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And replacing the values we got:

$W = -6.5 Kpa m^6 (\frac{1}{0.1 m^3}- \frac{1}{0.3 m^3})= -6.5 Kpa m^6 (6.66 m^-3) =-43.33 Kpa m^3 = -43.33 KJ$

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4 years ago

If a bearing needs 4. 0 s to solidify enough for impact, how high must the tower be?.

maks197457 [2]

The height of the tower is equal to 78.4 meters.
The bearing's impact velocity is equal to 39.2 m/s.

<h3>How to determine the height of the tower?</h3>

In order to determine the height of the tower, we would apply the second equation of motion and assume that the downward motion is negative.

Mathematically, the second equation of motion is given by this formula:

S = ut + ½gt²

Where:

S represents the distance or height.
u represents the initial velocity.
a represents the acceleration.
t represents the time.

Substituting the given parameters into the formula, we have;

S = S₀ + ut - ½gt²

0 = S₀ + (0)4.0 - ½ × (9.8) × 4.0²

0 = S₀ - 4.9 × 16.0

Height, S₀ = 78.4 meters.

<h3>How to calculate the bearing's impact velocity?</h3>

In order to calculate the bearing's impact velocity, we would apply the first equation of motion:

V = u - at

V = 0 - 9.8(4.0)

Impact velocity, V = 39.2 m/s.

Read more on velocity here: brainly.com/question/19365526

#SPJ1

Complete Question:

Ball bearings can be made by letting spherical drops of molten metal fall inside a tall tower, called a shot tower, and solidify as they fall.

a. If a bearing needs 4.0 s to solidify enough for impact, how high must the tower be?

b. What is the bearing's impact velocity?

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Answer:

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The paired shear forces that produces shear stress, act equally on the opposite sides of the given object.

<u>In the given example, the stress produced when using scissors for cutting, is known as the shear stress.</u>

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Answer:

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Answer:

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