1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ohaa [14]
3 years ago
12

Ronny has a hydraulic jack. The input force is 250 N, while the output force is 7,500 N. If the area of the pipe below the input

is 0.2 m2, what is the area of the pipe below the load?
Engineering
1 answer:
Ganezh [65]3 years ago
6 0

Answer:

6 m²

Explanation:

application of fluid pressure according to  Pascal's principle for the two pistons is given as:

P_1=P_2

Where P₁ is the pressure at the input and P₂ is the pressure at the output.

But P₁ = F₁ / A₁ and P₂ = F₂ / A₂

Where F₁ and F₂ are the forces applied at the input and output respectively and A₁ and A₂ are the area of  the input pipe and output pipe respectively

Since, P_1=P_2

\frac{F_1}{A_1} =\frac{F_2}{A_2}\\

But A₁ = 0.2 m², F₁ = 250 N, F₂ = 7500 N. Substituting values to get:

\frac{F_1}{A_1} =\frac{F_2}{A_2}\\\frac{250}{0.2}=\frac{7500}{A_2}\\  A_2=\frac{7500*0.2}{250} = 6m^2

Therefore, the area of the pipe below the load is 6 m²

You might be interested in
explain the four functional blocks on an oscilloscope and describe the major controls within each block
steposvetlana [31]

Answer:

The cathode ray oscilloscope (CRO) consists of a set of blocks. Those are vertical amplifier, delay line, trip circuit, time base generator, horizontal amplifier, cathode ray tube (CRT) and power supply. The CRO block diagram is shown in attached figure.

The function of each CRO block is mentioned below,

Vertical amplifier amplifies the input signal, which will be displayed on the CRT screen.

Delay line provides a certain amount of delay to the signal, which is obtained at the output of the vertical amplifier. This delayed signal is then applied to the CRT vertical deflection plates.

Trigger circuit produces a trigger signal to synchronize the horizontal and vertical deviations of the electron beam.

Time base generator produces a sawtooth signal, which is useful for horizontal deviation of the electron beam.

Horizontal amplifier amplifies the sawtooth signal and then connects it to the CRT horizontal deflection plates.

Power supply produces high and low voltages. The high negative voltage and the low positive voltage apply to CRT and other circuits respectively.

Cathode ray tube (CRT)

it is the main important block of CRO and consists mainly of four parts. Those are electronic guns, vertical deflection plates, horizontal deflection plates and fluorescent display.

The electron beam, which is produced by an electron gun, is deflected both vertically and horizontally by a pair of vertical deflection plates and a pair of horizontal deflection plates, respectively. Finally, the deflected beam will appear as a point on the fluorescent screen.

In this way, CRO will display the input signal applied on the CRT screen. So, we can analyze the signals in the time domain using CRO.

Explanation:

The oscilloscopes which is widely used for analysis purpose of circuits is divided into four main groups: the horizontal and vertical controls, the input controls and the activation controls.

Found in the front panel section marked Horizontal, the oscilloscope's horizontal controls allow users to adjust the horizontal scale of the screen. This section includes the control of the horizontal delay (displacement), as well as the control that indicates the time per division on the x-axis. The first control allows users to scan through a time range, while the latter allows users to approach a particular time range by decreasing the time per division.

Meanwhile, the oscilloscope's vertical controls are usually found in a section specifically marked as Vertical. The controls found in this section allow users to adjust the vertical appearance of the screen and include the control that indicates the number of volts per division on the axis and the grid of the screen. Also in this section is the control of the vertical displacement of the waveform, which translates the waveform up or down on the screen.

Signal activation helps provide a usable and stable display and allows users to synchronize the oscilloscope acquisition in the waveform of interest. The oscilloscope trigger controls allow users to choose the vertical trigger level, as well as the desired trigger capability. Common types of activation include fault activation, edge activation and pulse width activation.

Useful for identifying random errors or failures, the activation of faults allows users to fire at a pulse or event whose width is less than or greater than a specific period of time. This activation mode allows users to capture errors or technical problems that do not occur very frequently, which makes them very difficult to see.

The most famous trigger mode, edge tripping occurs when the voltage exceeds a set threshold value. This mode allows users to choose between shooting on a falling or rising edge.

Although pulse width activation is comparable to fault activation when users search for pulse width, it is, however, more general since it allows users to fire pulses of specified width. Users can also select the polarity of the pulses to be activated and set the horizontal position of the trigger. This allows users to see what happened during pre-shot or post-shot.

The input panels of an oscilloscope usually include two or four analog channels. They are usually numbered and have a button associated with each channel that allows users to activate and deactivate them. This section may also include a selection that allows users to specify the DC or AC coupling. Selecting the DC coupling implies that the entire signal will be input. The AC pairing, on the other hand, blocks the DC component and focuses the waveform around zero volts. Operators can also identify the probe impedance of the channels through a selection button. In adding, the input panels permit users to select the type of sampling to be used.

5 0
3 years ago
Answer the following questions in complete sentences. Make sure to explain your thinking.
trapecia [35]
BOY IS IN THE HOOD BOY IS IN THE HOOD
7 0
3 years ago
What is a thermal reservoir?
Mekhanik [1.2K]

Answer:

Explanation:

Thermal reservoir:

   It is the body which have infinite amount of heat capacity and store large amount of heat.The temperature of thermal reservoir is constant and does not change with time.The temperature of thermal reservoir is not change even heat is going out from reservoir or heat going inside the reservoir.The temperature of thermal reservoir remains constant and does not depend on the surroundings.

7 0
4 years ago
You have a 12 volt power source running through a circuit that has 3kΩ of resistance, how many amps (in mA) can flow through the
siniylev [52]

Answer:

4mA

Explanation:

For this problem, we will simply apply Ohm's law:

V = IR

V/R = I

I = V / R

I = 12 volt / 3kΩ

I = 4mA

Hence, the current in the circuit is 4mA.

Cheers.

5 0
3 years ago
Write a new ARMv8 assembly file called "lab04b.S" which is called by your main function. It should have the following specificat
Len [333]

Answer:

my_mul:

.globl my_mul

my_mul:

   //Multiply X0 and X1

   //   Does not handle negative X1!

   //   Note : This is an in efficient way to multipy!

   SUB SP, SP, 16       //make room for X19 on the stack

   STUR X19, [SP, 0]    //push X19

   ADD X19, X1, XZR     //set X19 equal to X1

   ADD X9 , XZR , XZR //set X9 to 0

mult_loop:

   CBZ X19, mult_eol

   ADD X9, X9, X0

   SUB X19, X19, 1

   B mult_loop

mult_eol:

   LDUR X19, [SP, 0]

   ADD X0, X9, XZR      // Move X9 to X0 to return

   ADD SP, SP, 16       // reset the stack

   BR X30

Explanation:

6 0
4 years ago
Other questions:
  • Tech distractions do NOT include _________.
    9·1 answer
  • Decide how the sketches below would be listed, if they were listed in order of decreasing force between the charges. That is, se
    9·1 answer
  • The dramatic growth in the number of power data centers, cell towers, base stations, recharge mobiles, and so on is damaging the
    8·1 answer
  • Refrigerant 22 undergoes a constant-pressure process within a piston–cylinder assembly from saturated vapor at 3.5 bar to a fina
    8·1 answer
  • A projectile is launched horizontally 1m above the ground. If it lands 300m away from the initial launch position, find: a)-the
    10·1 answer
  • Water flows through a nozzle at the end of a fire hose. If the nozzle exit velocity must be 20 m/s and the exit diameter is 40 m
    6·1 answer
  • Select the qualification that is best demonstrated in each example.
    11·2 answers
  • Programming Assignment 2 Decimal and IEEE-754 ConversionsObjective: To write a C program (not C++) that converts numbers between
    6·1 answer
  • For Figure Below, if the elevation of the benchmark A is 25.00 m above MSL:
    14·1 answer
  • Steam enters a heavily insulated throttling valve at 11 MPa, 600°C and exits at 5.5 MPa. Determine the final temperature of the
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!