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melamori03 [73]
3 years ago
14

Use the Lewis model to determine the formula for the compound that forms from each pair of atoms.

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

KI

Explanation:

K is 1+  & I is 1- so we need 1 of each to balance out the compound.

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A gas with a volume of 250 mL at a temperature of 293K is heated to 324K. What is the new volume of the gas?
Natalija [7]

Answer:

The new volume of the gas is 276.45 mL.

Explanation:

Charles's law indicates that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.

Charles's law is a law that mathematically says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\frac{V}{T} =k

Analyzing an initial state 1 and a final state 2, it is satisfied:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

  • V1= 250 mL
  • T1= 293 K
  • V2= ?
  • T2= 324 K

Replacing:

\frac{250 mL}{293 K} =\frac{V2}{324 K}

Solving:

V2=324 K*\frac{250 mL}{293 K}

V2= 276.45 mL

<em><u>The new volume of the gas is 276.45 mL.</u></em>

4 0
3 years ago
If an acid has a ka=1.6x10^-10, what is the acidity of the solution?
LUCKY_DIMON [66]
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
 In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+.  If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
5 0
3 years ago
This diagram is attempting to compare the sizes of the four inner planets. What is wrong with this diagram?
Simora [160]

Answer:

points

Explanation:

6 0
3 years ago
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In the cathode ray experiment, the cathode ray is seen to move from the negative disk to the positive disk. What kind of subatom
Tomtit [17]

Answer:

Gixt8x75zurx7txr7x7tzzr7zr7z64zz7z84

8 0
3 years ago
In an experiment, a 0.5297 g sample of diphenylacetylene (C14H10) is burned completely in a bomb calorimeter. The calorimeter is
V125BC [204]

Answer:

the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

Explanation:

Given that:

mass of diphenylacetylene (C_{14}H_{10}) = 0.5297 g

Molar Mass of diphenylacetylene (C_{14}H_{10}) = 178.21 g/mol

Then number of moles of diphenylacetylene (C_{14}H_{10})  = \frac{mass}{molar \ mass}

= \frac{0.5297  \ g }{178.24 \  g/mol}

= 0.002972 mol

By applying the law of calorimeter;

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = Heat absorbed by H_2O + Heat absorbed  by the calorimeter

Heat liberated  by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  =  msΔT + cΔT

= 1369 g  × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C

= 17756.48 J + 2842.39 J

= 20598.87 J

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = 20598.87 J

Heat liberated by 1 mole of  diphenylacetylene (C_{14}H_{10}) will be = \frac{20598.87 \ J}{0.002972 \ mol}

= 6930979.139 J/mol

= 6930.98 kJ/mol

Since heat is liberated ; Then, the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

3 0
3 years ago
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