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3 years ago

M∠A+ m∠B = ? How do you know this?

Mathematics

1 answer:

pychu [463]3 years ago

4 0

Answer:

Step-by-step explanation:

If m∠A + m∠B = m∠B + m∠C, subtract m∠B from both sides [ subtraction property of equality ].

We get that m∠A = m∠C and by the symmetric property of equality, m∠C = m∠A

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Which of the following equations is of a parabola with a vertex at (0, -5)

Harlamova29_29 [7]

The x, which is zero in this case will always be the number that goes on the inside of the equation, so far you have y=(x+0)^2 or y=x^2.

The y, which is negative will go on the end of the equation. So you get y=x^2-5

The equation is y=x^2-5 or C if it is multiple choice

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3 years ago

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nikklg [1K]

Answer:

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3 years ago

A painting is 24 in. Wide by 32in. Long. The width of a postcard reductions of the painting is 3in. How long is the postcard

s344n2d4d5 [400]

Answer:

4 inches.

Step-by-step explanation:

24 32

---- = -----

3 x

Cross multiply.

24x = (32)(3) = 96.

96 / 24 = 4.

Hope this helped and good luck! (:

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3 years ago

(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw

slavikrds [6]

Answer:

a. $\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. $C_{0}=122$

c. $k=-0.00259$

d. $t=153.39838\\$ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

$Tm=68$

$\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. The differential equation obtained is a differential equation of separable variables:

$\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122$