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telo118 [61]
3 years ago
9

The mean orbital radius of the earth around the sun 1.5 × 108 km. Calculate the

Physics
1 answer:
Readme [11.4K]3 years ago
5 0

Answer:

M = 1.994 × 10^(30) kg

Explanation:

We are given;

Orbital radius; r = 1.5 × 10^(8) km = 1.5 × 10^(11) m

Gravitational constant; G = 6.67 × 10^(-11) N.m²/kg²

If the orbit is circular, the it means the gravitational force is equal to the centripetal force.

Thus; F_g = F_c

GMm/r² = mv²/r

Simplifying gives;

GM/r = v²

M = v²r/G

Now, v is the speed of the earth around the sun and from online sources it has a value of around 29.78 km/s = 29780 m/s

Thus;

M = (29780^(2) × 1.5 × 10^(11))/6.67 × 10^(-11)

M = 1.994 × 10^(30) kg

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a parent swings a 18.5 kg child in a circle of radius 1.05m, making 5 revolutions in 13.4s. what centripetal acceleration does t
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On the other hand, the tangential velocity  is expressed as:

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Where \omega is the angular velocity, which can be found knowing the child makes 5 revolutions in 13.4s:

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