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dangina [55]
3 years ago
8

WILL MARK THE BRAINLIEST!!! The diagram shows a carrier wave that is used to transmit information. Which best illustrates how th

e carrier wave would likely appear after pulse modulation?

Physics
2 answers:
Sholpan [36]3 years ago
8 0

Answer:

Second image in your list of possible answers

Explanation:

The second option is what you would expect from modulating a sinusoidal carrier wave of higher frequency after being modulated by a square pulse of lower frequency that allows part of the carrier signal to travel during the time the square signal is constant different from zero, and be absent (flat) during the time the square pulse signal has amplitude zero.

OlgaM077 [116]3 years ago
4 0

The second line is the best picture of a pulse-modulated carrier.

It would be easy to build a circuit where each pulse ... when it comes along ... just switches the carrier OFF for as long as the pulse lasts.

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Calculate the force between two objects that have masses of 70 kilograms and 2,000 kilograms separated by a distance of 1 meter.
Makovka662 [10]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The Gravitational Force between given objects will be ~

  • 9.34 \times  {10}^{ - 6}  \:  \: N

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

We know that ~

\huge\boxed{\mathrm{F = \dfrac{ Gm_1m_2}{ r²}}}

where ~

  • F = gravitational force

  • m_1 = mass of 1st object = 70 kg

  • m_2 = mass of 2nd object = 2000 kg

  • G = gravitational constant = 6.674 × {10}^ {-11}

  • r = distance between the objects = 1 m

Let's calculate the force ~

  • F =  \dfrac{6.674 \times 10 {}^{ - 11} \times 70 \times 2000 }{1 {}^{2} }

  • F =6.674 \times 7 \times 2 \times 10 { }^{ - 11} \times 10 {}^{4}

  • 93.436 \times 10 {}^{ - 7}

  • 9.3436  \times 10 {}^{ - 6} \:  \:  newtons
6 0
3 years ago
A 41-turn square coil of area 0.074 m2 and a 123-turn circular coil are both placed perpendicular to the same changing magnetic
vesna_86 [32]

Answer:

<h3>The area of second coil is ≅ 0.025 m^{2}</h3>

Explanation:

Given :

No. of turns in the first coil N_{1} = 41

No. of turns in the second coil N_{2}  = 123

Area of first coil A_{1} = 0.074 m^{2}

According to the law of electromagnetic induction,

Induced emf = -N \frac{d \phi}{dt}

Where \phi = magnetic flux.

Since given in question emf of both coil is same so we compare above equation.

    -\frac{N_{1} d\phi _{1}   }{dt_{1} }  = -\frac{N_{2} d\phi _{2}   }{dt_{2} }

   \frac{N_{1} A_{1}   dB_{1}  }{dt_{1} }  = \frac{N_{2} A_{2} dB_{2}     }{dt_{2} }

        A_{2} = \frac{N_{1} A_{1}  }{N _{2}  }

        A_{2} = \frac{41 \times 0.074 }{123  }

        A_{2} = 0.0246 = 0.025 m^{2}

Therefore, the area of second coil is ≅ 0.025 m^{2}

4 0
4 years ago
An electron is pushed into an electric field where it acquires a 1-V electrical potential. Suppose instead that two electrons ar
sleet_krkn [62]

Answer:

0.5 V

Explanation:

The electric potential distance between different locations in an electric field area is unaffected by the charge that is transferred between them. It is solely dependent on the distance. Thus, for two electrons pushed together at the same distance into the same field, the electric potential will remain at 1 V. However, the electric potential of one of the two electrons will be half the value of the electric potential for the two electrons.

6 0
3 years ago
What is the variable that is manipulated by the experimenter during an experiment called
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Independent variable
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4 years ago
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