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White raven [17]
3 years ago
11

How do you answer this for a elimination simulatoneons equation

Mathematics
2 answers:
Margaret [11]3 years ago
5 0
First you multiply both equations by 5 and 3
Then you take away both the equations form one another
Next you divide by 4 to get y on its own
This gives you y - which is 4

Then you choose one equation from your question. I chose 3x + 2y = 14 because it looks easier
Input your y value (that you just worked out before) into the y on this equation
Get x on its own by minusing 8 then dividing by 3
This gives you x - which is 2


Ive put a picture incase you still do not understand

denis23 [38]3 years ago
3 0

\it 3x+2y=14
\\
5x-2y=18
\\
------\\
8x \ \ \ \ \ \ \  =32 \Rightarrow x = 32:8\Rightarrow x=4 \ \ \ (*)

\it 3x+2y=14 \stackrel{(*)}{\Longrightarrow} 3\cdot4+2y=14 \Rightarrow 12+2y=14 \Rightarrow 2y=14-12\Rightarrow 
\\\;\\
\Rightarrow 2y=2 \Rightarrow y=2:2 \Rightarrow y=1

Therefore, the solution is:  x = 4,  y=1.


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